Question

Write the type of reaction
Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated ${H_2}S{O_4}$
A.Esterification reaction
B.Neutralization reaction
C.Decomposition reaction
D.Double displacement reaction

Answer 1

Hint: Ethanol is always liquid at room temperature and has a melting point of 156K. It is one of the most active ingredients in alcoholic beverages. It basically undergoes an esterification reaction when warmed with ethanoic acid.

Complete step by step answer:
Esterification reaction refers to the reaction in which a carboxylic acid reacts with alcohol and ester is formed. This reaction can further be regarded as the transformation of carboxylic acids or their derivatives into esters. Moreover, the name of an ester is derived from its carboxylic acid that takes part in the esterification reaction
Now, when ethanol is warmed with ethanoic acid in presence of concentration, ${H_2}S{O_4}$ ethyl acetate is formed. The reaction is as shown:
 ${C_2}{H_5}OH + C{H_3}COOH\xrightarrow{{{H^ + }}}C{H_3}COO{C_2}{H_5} + {H_2}O$
This reaction is known as an esterification reaction because alcohol and acid are combined to form an ester.
Basically, esterification can happen in three different ways:
-From acid anhydride and alcohol
-From acid chloride and alcohol
-From carboxylic acid and alcohol

Hence, option A is correct.

Note:
Esters are commonly used in the manufacturing of surfactants like detergents and soaps. They are also used in perfumes, cosmetics and as food flavoring agents. Moreover, they are also used in the manufacturing of medicines, paints and dyes. Always remember that Esters possess a carbon-carbonyl oxygen bond whereas ether possess a carbon-oxygen carbon bond.