Courses
Courses for Kids
Free study material
Offline Centres
More
Store

Write the smallest digit and the greatest digit in the blank space each of the following number so that the number formed is divisible by $3$ ?$\_6724$

Last updated date: 21st Jun 2024
Total views: 413.7k
Views today: 5.13k
Verified
413.7k+ views
Hint:First we need to find the smallest digit and greatest digit in the given number so that it is formed and it is divisible by $3$.Also we need to know the definition of divisibility test of $3$.A number is divisible by $3$ if the sum of its digits is divisible by $3$.Using this rule and doing some calculations on it Finally we will get the required digits.

It is given that the given number is $\_6724$
We have to find the blank space at smallest and greatest digit and it is divisible by $3$
A number is divisible by $3$ if the sum of its digits is divisible by$3$.
Now we have to sum of digits in the given number =$\_ + 6 + 7 + 2 + 4 = \_ + 19$
We can see here on simplifications the digits which when added them in the result $\left( {19} \right)$ gives the final number will divisible by $3$
Hence we got the smallest digit will be $2$ which will be of the form $26724$ and we got the greatest digit will be $8$ which will be of the form $86724$.
Note:In such types of questions the key concept we have to remember is that there is always the divisibility rule of $3$ which is stated above.