
Write the reciprocal of $-5$
Answer
585.9k+ views
Hint: A reciprocal of a fraction is done by changing the position of numerator and denominator. To locate the proportional of a discerning articulation - any normal articulation - you should simply flip the numerator and the denominator.
Complete step-by-step solution -
If ${\dfrac{x}{y}}$ is the fraction for which reciprocal is needed, then its reciprocal is ${\dfrac{y}{x}}$ .
Here, we need a reciprocal of $-5$.
So, the denominator is one and the numerator is $5$.
The numerator is stated as -5 and the denominator is one, as nothing in the denominator, and then divide or multiply a number by one, there is no change. Consider one as a denominator.
Begin by finding the reciprocal of \[\dfrac{x}{y}\], the reciprocal is \[\dfrac{y}{x}\]
So as to include the all terms together, it should locate a shared factor. Locate the shared factor by increasing the three unique terms in the denominator (x, y). Our shared factor will be xy. Put each term into terms of this shared factor:
The reciprocal of a negative number must itself be a negative number with the goal that the number and its equal duplicate to 1.
The numerator has expressed this solution, and the denominator is one as nothing in the denominator, and afterward separate or various a number by one, there is no change. So, we can accept one in the denominator.
So, in $-5$ the numerator is $-5$.
And denominator is 1
On reciprocating, the numerator becomes one and the denominator becomes $-5$.
So reciprocal of $-5$ is $ {-\dfrac{1}{5}}$.
Note: Reciprocal can be found by changing the position of the numerator and the denominator. It can be checked by multiplying the two expressions together and ensuring that your answer is 1. It must be done when the first portion numerator is unique in the relation to zero.
Complete step-by-step solution -
If ${\dfrac{x}{y}}$ is the fraction for which reciprocal is needed, then its reciprocal is ${\dfrac{y}{x}}$ .
Here, we need a reciprocal of $-5$.
So, the denominator is one and the numerator is $5$.
The numerator is stated as -5 and the denominator is one, as nothing in the denominator, and then divide or multiply a number by one, there is no change. Consider one as a denominator.
Begin by finding the reciprocal of \[\dfrac{x}{y}\], the reciprocal is \[\dfrac{y}{x}\]
So as to include the all terms together, it should locate a shared factor. Locate the shared factor by increasing the three unique terms in the denominator (x, y). Our shared factor will be xy. Put each term into terms of this shared factor:
The reciprocal of a negative number must itself be a negative number with the goal that the number and its equal duplicate to 1.
The numerator has expressed this solution, and the denominator is one as nothing in the denominator, and afterward separate or various a number by one, there is no change. So, we can accept one in the denominator.
So, in $-5$ the numerator is $-5$.
And denominator is 1
On reciprocating, the numerator becomes one and the denominator becomes $-5$.
So reciprocal of $-5$ is $ {-\dfrac{1}{5}}$.
Note: Reciprocal can be found by changing the position of the numerator and the denominator. It can be checked by multiplying the two expressions together and ensuring that your answer is 1. It must be done when the first portion numerator is unique in the relation to zero.
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