
Write the place value of the underlined digit of the following decimal numbers:
$\left( i \right)82.\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{6} 1$
$\left( {ii} \right)5.\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{2} 4$
Answer
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Hint: The number which is directly after the decimal point is marked to be at the tenth place and then the next one on the right to this number is then at hundredth place and it goes on like this only.
Complete Step-by-Step solution:
As we know in the number system after the decimal firth place is called as tenths second place is called as hundreds third place is called as thousand and so on….
So in a given decimal number we have to calculate the place value of the underlined digit.
$\left( i \right)82.\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{6} 1$
So in this given decimal number the underlined digit is 6 which comes just after the decimal so the place value of 6 is tenths according to the above information.
$\left( {ii} \right)5.\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{2} 4$
So in this given decimal number the underlined digit is 2 which comes just after the decimal so the place value of 2 is tenths according to the above information.
So this is the required place value of the underlined digits.
So this is the required answer.
Note: Whenever we face such type of problems the key point is regarding the basic understand of the place value of a digit, to the left of decimal is keeps on increasing from tenth to hundredth to thousandth up to so on however this increment in place value is found towards the right after the decimal.
Complete Step-by-Step solution:
As we know in the number system after the decimal firth place is called as tenths second place is called as hundreds third place is called as thousand and so on….
So in a given decimal number we have to calculate the place value of the underlined digit.
$\left( i \right)82.\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{6} 1$
So in this given decimal number the underlined digit is 6 which comes just after the decimal so the place value of 6 is tenths according to the above information.
$\left( {ii} \right)5.\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{2} 4$
So in this given decimal number the underlined digit is 2 which comes just after the decimal so the place value of 2 is tenths according to the above information.
So this is the required place value of the underlined digits.
So this is the required answer.
Note: Whenever we face such type of problems the key point is regarding the basic understand of the place value of a digit, to the left of decimal is keeps on increasing from tenth to hundredth to thousandth up to so on however this increment in place value is found towards the right after the decimal.
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