Question

Write the place value of $2$ in the following decimal number: \[9.42\]

Answer 1

Hint: Every digit in a number gets a value with respect to its position in the number. Since the given number is a decimal number, we will split the given number into a sum of fractions. This will easily indicate the place value of the digit $2$ in the given number.

Complete step-by-step answer:
Let $abc$ be a number where $a$, $b$ and $c$ are the digits in the number. Every number $abc$ can be split in the following manner, $abc=100\times a+10\times b+1\times c$.
If the number is a decimal number, then we can split the number as a sum of fractions. That is, if the number $x.yz$ is a decimal number where $x$, $y$ and $z$ are the digits in the number, we can write it as follows, $x.yz=1\times x+\dfrac{y}{10}+\dfrac{z}{100}$.
The given number is \[9.42\]. We can write it as shown above in the following manner,
$9.42=1\times 9+\dfrac{4}{10}+\dfrac{2}{100}$. So, we now know that the place value of $2$ in \[9.42\] is one hundredth.

Note: It is important to understand how to write any number according to its place values. This helps in doing arithmetic, especially for the decimal numbers. It is necessary to understand the difference between face value and place value of a digit. The face value of a digit is the value of the digit itself. The place value of a digit is the numerical value assigned to a digit due to its position in the number.