Question

Write the IUPAC names of the given compounds:

Answer 1

Hint:We know that the IUPAC nomenclature of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC). In the above stated compound, first of all we need to identify the functional group. Second we need to find out the longest parent chain and last we need to determine the ‘suffix’.

Complete answer:
For determining the IUPAC name, we need to follow some steps which are defined below:
First of all, we need to identify the functional group and here the functional group is alkene. So, we will use the prefix ‘ene’. Secondly, we need to determine the longest chain that will include the double bond (C=C). In the given diagram, we can see that the longest chain contains 5 carbon atoms and so we can determine the suffix ‘pent’ since 5 carbon atoms are present in the pentane group of organic compounds. longest chain. the double

Now that we know the suffix and the prefix, we will number the chain properly such that alkene is connected to the carbon atoms having highest priority but here according to IUPAC convention, numbering is done such that higher priority group like −OH in given compound could get less numbering. The group is present at ${1^{st}}$ carbon.
Now we will identify the branches. Ethyl group is present at ${4^{th}}$ carbon and a methyl group is present at ${2^{nd}}$ carbon.
Therefore, the IUPAC name of the given compound is 4-ethyl,2-methyl pent-4-ene-1-ol

Note:
We should note that the identification of the functional groups, if there are any, and naming them by their ionic prefixes such as hydroxy for -OH, oxy for =O, oxyalkylene for O-R, etc. Different side-chains and functional groups should be grouped together in alphabetical order.