
Write the IUPAC name of the following compound: $C{{H}_{3}}COC{{H}_{2}}CH=CHCON{{H}_{2}}$
Answer
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Hint: IUPAC is a worldwide accepted naming system. To name this compound, firstly identify the functional groups present here. Then count the number of carbon atoms here in the parent chain. Combining the two functional group names and the parent carbon chain will give you the IUPAC name of the given structure.
Complete step by step answer:
We know that IUPAC nomenclature is a method of naming chemical compounds as recommended by the International Union of Pure and Applied Chemistry. There are certain steps that we have to follow while writing the IUPAC name of any compound.
Firstly, let us write the structure and number the carbon atoms in it.
While naming the carbon atoms, we must remember to name it along the functional group. Here, we have one –oxo group (that is the double bonded oxygen atom to the carbon atom, numbered 5 in the structure) and an enamide group (that is the –CO along with the amide group numbered 1).
In the next step, we have to count the number of carbon atoms in the given compound.
As we can see we have 6 carbon atoms so there will be a ‘hex’ in the IUPAC name.
Now let us try to structure the IUPAC name.
We have Oxo group in the fifth position and enamide group in the second position. So it will have 5-oxo and 2-enamide. Now, to this we will simply include the number of carbon atoms present. We cannot end the IUPAC name on –oxo so we will add enamide to the suffix. So the IUPAC name will come out to be 5-oxohex-2-enamide.
Therefore, the correct answer is 5-oxohex-2-enamide is the IUPAC name of the compound $C{{H}_{3}}COC{{H}_{2}}CH=CHCON{{H}_{2}}$.
Note: To write the IUPAC name of any compound, we should remember the basic principle that while naming any compound in its IUPAC name, we generally start with the number of carbons in the parent chain. In the suffix, we have the name of the functional group attached to the parent chain. The other groups which are present are the substituents.
Complete step by step answer:
We know that IUPAC nomenclature is a method of naming chemical compounds as recommended by the International Union of Pure and Applied Chemistry. There are certain steps that we have to follow while writing the IUPAC name of any compound.
Firstly, let us write the structure and number the carbon atoms in it.
While naming the carbon atoms, we must remember to name it along the functional group. Here, we have one –oxo group (that is the double bonded oxygen atom to the carbon atom, numbered 5 in the structure) and an enamide group (that is the –CO along with the amide group numbered 1).
In the next step, we have to count the number of carbon atoms in the given compound.
As we can see we have 6 carbon atoms so there will be a ‘hex’ in the IUPAC name.
Now let us try to structure the IUPAC name.
We have Oxo group in the fifth position and enamide group in the second position. So it will have 5-oxo and 2-enamide. Now, to this we will simply include the number of carbon atoms present. We cannot end the IUPAC name on –oxo so we will add enamide to the suffix. So the IUPAC name will come out to be 5-oxohex-2-enamide.
Therefore, the correct answer is 5-oxohex-2-enamide is the IUPAC name of the compound $C{{H}_{3}}COC{{H}_{2}}CH=CHCON{{H}_{2}}$.
Note: To write the IUPAC name of any compound, we should remember the basic principle that while naming any compound in its IUPAC name, we generally start with the number of carbons in the parent chain. In the suffix, we have the name of the functional group attached to the parent chain. The other groups which are present are the substituents.
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