Answer
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Hint: Here we will arrange the rational numbers in ascending order by using the concept of LCM and by making the denominator the same for each rational number.
Complete step-by-step answer:
The L.C.M of 7, 2, and 4 is 28.So, convert the denominator to 28, in all rational numbers
$
\Rightarrow \dfrac{{ - 3}}{7} = \dfrac{{ - 3 \times 4}}{{7 \times 4}} = \dfrac{{ - 12}}{{28}} \\
\Rightarrow \dfrac{{ - 3}}{2} = \dfrac{{ - 3 \times 14}}{{2 \times 14}} = \dfrac{{ - 42}}{{28}} \\
\Rightarrow \dfrac{{ - 3}}{4} = \dfrac{{ - 3 \times 7}}{{4 \times 7}} = \dfrac{{ - 21}}{{28}} \\
$
Now it is clear that
$\dfrac{{ - 42}}{{28}} < \dfrac{{ - 21}}{{28}} < \dfrac{{ - 12}}{{28}} \Rightarrow \dfrac{{ - 3}}{2} < \dfrac{{ - 3}}{4} < \dfrac{{ - 3}}{7}$
So this is your required ascending order.
Note: In this type of questions always take the L.C.M of the denominator, then make all the rational numbers denominator same to the L.C.M value, by appropriate multiplication in numerator and denominator.
Complete step-by-step answer:
The L.C.M of 7, 2, and 4 is 28.So, convert the denominator to 28, in all rational numbers
$
\Rightarrow \dfrac{{ - 3}}{7} = \dfrac{{ - 3 \times 4}}{{7 \times 4}} = \dfrac{{ - 12}}{{28}} \\
\Rightarrow \dfrac{{ - 3}}{2} = \dfrac{{ - 3 \times 14}}{{2 \times 14}} = \dfrac{{ - 42}}{{28}} \\
\Rightarrow \dfrac{{ - 3}}{4} = \dfrac{{ - 3 \times 7}}{{4 \times 7}} = \dfrac{{ - 21}}{{28}} \\
$
Now it is clear that
$\dfrac{{ - 42}}{{28}} < \dfrac{{ - 21}}{{28}} < \dfrac{{ - 12}}{{28}} \Rightarrow \dfrac{{ - 3}}{2} < \dfrac{{ - 3}}{4} < \dfrac{{ - 3}}{7}$
So this is your required ascending order.
Note: In this type of questions always take the L.C.M of the denominator, then make all the rational numbers denominator same to the L.C.M value, by appropriate multiplication in numerator and denominator.
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