Question

Write the following number in the form\[10a + b\]:
\[56\]

Answer 1

Hint: A two-digit number having \[a\] and \[b\] as its digits at the tens and the ones places respectively is written in the generalized form as \[10a + b\], that is in general, a two-digit number can be written as \[10a + b\],where '\[a\]' can be any of the digits from \[1\] to \[9\] and '\[b\]' can be any of the digits from \[0\] to\[9\].
So we can easily express any two digit number in the form of \[10a + b\] by multiplying the first digit by \[10\] then adding it with the second digit.

Complete step-by-step answer:
The given number is \[56\]. we need to write the number in the form \[10a + b\].
We know that, a two-digit number can be written as \[10a + b\], where '\[a\]' can be any of the digits from \[1\] to \[9\] and '\[b\]' can be any of the digits from \[0\] to \[9\].
So, we can easily express \[56\] in the form of \[10a + b\] by multiplying \[5\] by \[10\] then adding it with \[6\].
Therefore we get,
\[56 = 5 \times 10 + 6\].

Note: Generalized Form:
A number is said to be in a generalized form if it is expressed as the sum of the product of its digits with their respective place values.
Thus, a two-digit number having \[a\] and \[b\] as its digits at the tens and the ones place respectively is written in the generalized form as \[10a + b\].
That is in general, a two-digit number can be written as\[10a + b\], where ‘\[a\]’ can be any of the digits from \[1\] to \[9\] and ‘\[b\]’ can be any of the digits from \[0\] to \[9\].
Similarly, a three-digit number can be written in the generalized form as \[100a + 10b + c\], where ‘\[a\]’ can be any one of the digits from \[1\] to \[9\] while ‘\[b\]’ and ‘\[c\]’ can be any of the digits from \[0\] to \[9\].