
Write the equilibrium constant expression for the decomposition of the baking soda. Deduce the unit from the above expression.
Answer
532.5k+ views
Hint:The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients. The ratio of concentration of products and reactants at equilibrium will be the required equilibrium constant
Complete step-by-step answer:We know that The equilibrium constant of a chemical reaction (usually denoted by the symbol K) provides insight into the relationship between the products and reactants when a chemical reaction reaches equilibrium. For example, the equilibrium constant of concentration (denoted by Kc) of a chemical reaction at equilibrium can be defined as the ratio of the concentration of products to the concentration of the reactants, each raised to their respective stoichiometric coefficients
So the decomposition reaction of baking soda which is sodium bicarbonate is as follows
$2NaHCO_3(s) \rightleftharpoons Na_2CO_3(s)+Co_2(g)+H_2O(g)$
The equilibrium constant can be written as
$K_c = \dfrac{[Na_2CO_3][CO_2][H_2O]}{{[Na_2CO_3]^2}}$
Pure solid concentration is taken as unity
Then $K_c = [CO_2][H_2O]$
The units of $K_c$ are = $(mol\,\, dm^{-3}.\,\,mol\,\,\, dm^{-3})$
So the units of $K_c$ are = $mol^{2}\,\,dm^{-6}$
So the equilibrium constant $K_c$ = $[CO_2][H_2O]$ and the units are $mol^{2}\,\,dm^{-6}$
Note: For a chemical reaction, the equilibrium constant can be defined as the ratio between the amount of reactant and the amount of product which is used to determine chemical behaviour.
At equilibrium, Rate of the forward reaction = Rate of the backward reaction
Complete step-by-step answer:We know that The equilibrium constant of a chemical reaction (usually denoted by the symbol K) provides insight into the relationship between the products and reactants when a chemical reaction reaches equilibrium. For example, the equilibrium constant of concentration (denoted by Kc) of a chemical reaction at equilibrium can be defined as the ratio of the concentration of products to the concentration of the reactants, each raised to their respective stoichiometric coefficients
So the decomposition reaction of baking soda which is sodium bicarbonate is as follows
$2NaHCO_3(s) \rightleftharpoons Na_2CO_3(s)+Co_2(g)+H_2O(g)$
The equilibrium constant can be written as
$K_c = \dfrac{[Na_2CO_3][CO_2][H_2O]}{{[Na_2CO_3]^2}}$
Pure solid concentration is taken as unity
Then $K_c = [CO_2][H_2O]$
The units of $K_c$ are = $(mol\,\, dm^{-3}.\,\,mol\,\,\, dm^{-3})$
So the units of $K_c$ are = $mol^{2}\,\,dm^{-6}$
So the equilibrium constant $K_c$ = $[CO_2][H_2O]$ and the units are $mol^{2}\,\,dm^{-6}$
Note: For a chemical reaction, the equilibrium constant can be defined as the ratio between the amount of reactant and the amount of product which is used to determine chemical behaviour.
At equilibrium, Rate of the forward reaction = Rate of the backward reaction
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

