
How do you write the equation given slope $2$ and passes through $( - 2, - 5)?$
Answer
544.2k+ views
Hint:
As we know that the given equation that can be formed is a linear equation in two variables. An equation of the form $px + qy = r$, where $p,q$ and $r$ are real numbers and the variables $p$ and $q$ are not equivalent to zero, is called linear equation in two variables. The slope intercept form of a linear equation has the following term where the equation is solved for $y$ in terms of $x:y = a + bx$, $b$ is the slope and $a$ is a constant term.
Complete step by step solution:
We will rewrite the standard form of linear equation: $ax + by = c$. The slope intercept form of the equation is $y = mx + b$.
Here we have $x = - 2$ and $y = - 5$, the slope i.e. $m = 2$. Now we substitute all the values in the equation $y = mx + b$, we get $ - 5 = 2 \times - 2 + b$, on further solving we have $ - 5 = - 4 + b \Rightarrow b = - 5 + 4 = 1$.
So the given equation is $2x - y - 1 = 0$.
Hence the slope intercept form of the above equation is $2x - y - 1 = 0$.
Note:
We know that the formula of slope intercept form is $y = mx + b$ where $y$is the “y” coordinate, $m$is the slope, $x$is the “x” coordinate and $b$is the ‘y’ intercept. We can use this form of linear equation to draw the graph of the given equation on the “x” and “y” coordinate plane. We should keep in mind that the conversion of the equation of the line to slope intercept form is done by simple manipulation. $Y$intercept of the line is the point where the line cuts the ‘y’ axis and the slope is tan of the angle that is made by the line on the x- axis.
As we know that the given equation that can be formed is a linear equation in two variables. An equation of the form $px + qy = r$, where $p,q$ and $r$ are real numbers and the variables $p$ and $q$ are not equivalent to zero, is called linear equation in two variables. The slope intercept form of a linear equation has the following term where the equation is solved for $y$ in terms of $x:y = a + bx$, $b$ is the slope and $a$ is a constant term.
Complete step by step solution:
We will rewrite the standard form of linear equation: $ax + by = c$. The slope intercept form of the equation is $y = mx + b$.
Here we have $x = - 2$ and $y = - 5$, the slope i.e. $m = 2$. Now we substitute all the values in the equation $y = mx + b$, we get $ - 5 = 2 \times - 2 + b$, on further solving we have $ - 5 = - 4 + b \Rightarrow b = - 5 + 4 = 1$.
So the given equation is $2x - y - 1 = 0$.
Hence the slope intercept form of the above equation is $2x - y - 1 = 0$.
Note:
We know that the formula of slope intercept form is $y = mx + b$ where $y$is the “y” coordinate, $m$is the slope, $x$is the “x” coordinate and $b$is the ‘y’ intercept. We can use this form of linear equation to draw the graph of the given equation on the “x” and “y” coordinate plane. We should keep in mind that the conversion of the equation of the line to slope intercept form is done by simple manipulation. $Y$intercept of the line is the point where the line cuts the ‘y’ axis and the slope is tan of the angle that is made by the line on the x- axis.
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