How do you write the equation for a circle with center at $\left( {2,3} \right)$ that is tangent to the x-axis?
Answer
603.6k+ views
Hint: In this question we are asked to find the equation of circle whose radius is given, and to so this we use the standard form of equation of circle which is given by ${\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2}$, where $\left( {h,k} \right)$ is the centre of the circle and$r$is the radius of the circle, and tangent to x-axis means the radius will be y-coordinate of the center i.e., 3, now substituting the values in the equation of the circle we will get the required equation.
Complete step by step answer:
Given radius is $\left( {2,3} \right)$,
So we know that standard form of equation of circle is given by ${\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2}$, where $\left( {h,k} \right)$ is the centre of the circle and ris the radius of the circle,
Now here $\left( {h,k} \right) = \left( {2,3} \right)$ i.e., $h = 2$and $k = 3$,
And also it is given that the equation is tangent to the x-axis, so we know that if the equation is tangent to x-axis that means the radius will be y-coordinate of the center i.e., 3, $r = 3$,
Now substituting the values in the equation of circle we get,
$ \Rightarrow {\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = {3^2}$,
Now simplifying we get,
$ \Rightarrow {\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = 9$,
So, the equation of the circle is ${\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = 9$.
$\therefore $ The equation for a circle with center at $\left( {2,3} \right)$ that is tangent to the x-axis is given by ${\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = 9$.
Note: In solving these type of questions we should know the general equation of the circle ${\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2}$ also it is important to note that sometimes we should use the complete the square method with respect to $x$ and $y$ so that we obtain the equation in general from. And another general equation of a circle is ${x^2} + {y^2} + 2gx + 2fy + c = 0$.
Complete step by step answer:
Given radius is $\left( {2,3} \right)$,
So we know that standard form of equation of circle is given by ${\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2}$, where $\left( {h,k} \right)$ is the centre of the circle and ris the radius of the circle,
Now here $\left( {h,k} \right) = \left( {2,3} \right)$ i.e., $h = 2$and $k = 3$,
And also it is given that the equation is tangent to the x-axis, so we know that if the equation is tangent to x-axis that means the radius will be y-coordinate of the center i.e., 3, $r = 3$,
Now substituting the values in the equation of circle we get,
$ \Rightarrow {\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = {3^2}$,
Now simplifying we get,
$ \Rightarrow {\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = 9$,
So, the equation of the circle is ${\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = 9$.
$\therefore $ The equation for a circle with center at $\left( {2,3} \right)$ that is tangent to the x-axis is given by ${\left( {x - 2} \right)^2} + {\left( {y - 3} \right)^2} = 9$.
Note: In solving these type of questions we should know the general equation of the circle ${\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2}$ also it is important to note that sometimes we should use the complete the square method with respect to $x$ and $y$ so that we obtain the equation in general from. And another general equation of a circle is ${x^2} + {y^2} + 2gx + 2fy + c = 0$.
Recently Updated Pages
Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

