Question

Write the chemical names of ${\text{C}}{{\text{H}}_{\text{3}}}{\text{COC}}{{\text{H}}_{\text{3}}}$ and ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{COOH}}$.

Answer 1

Hint:
-We have to name the given chemical compounds. So, identify it step by step, i.e.
-Identify the presence of the functional groups in both the compounds like OH, COOH, CO, etc.
-Count the number of carbon atoms, according to that we can name it like meth, eth, prop etc.
-Finally combining step 1, and step 2; the name will be known.

Complete step by step answer:
-First, we will name the chemical compound -${\text{C}}{{\text{H}}_{\text{3}}}{\text{COC}}{{\text{H}}_{\text{3}}}$. Let us move step by step as mentioned.
-In this, the functional group identified is C=O, i.e. a ketone group. While naming the compound the suffix is being added, i.e. ‘-one’
-If we count the number of carbon atoms, i.e. 3. So, we know for the 3 carbon atoms the root name is ‘prop’
-Finally, we can say the name of the chemical compound is propanone.
Second, we will name the chemical compound -${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{COOH}}$. Let us move step by step as mentioned above.
-In this compound, -COOH is the functional group, also known to be a carboxylic acid. So, the suffix will be ‘-oic acid’
-As we can see the total number of carbon atoms is 3. Therefore, the root name is ‘prop’
-Finally, we can say the name of the chemical compound is propanoic acid.
In the last, we can conclude that the chemical name of -${\text{C}}{{\text{H}}_{\text{3}}}{\text{COC}}{{\text{H}}_{\text{3}}}$ and -${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}{\text{COOH}}$ is propanone, and propanoic acid respectively.

Note: Don’t get confused while naming the chemical compound just move step by step. Think carefully while identifying the presence of a functional group in the compound. Both compounds have 3 carbon atoms, but the major difference is the presence of a functional group. So, it is mandatory to identify carefully as it can change the name of a compound.