
Write the chemical formula for:
A. Nitrogen dioxide
B. Carbon monoxide
C. Oxygen gas
D. Sulphur dioxide
Answer
560.1k+ views
Hint:First we should be aware of the molecules we are talking about. They are inorganic compounds and they have a specific kind of naming. Now we just have to follow the naming which is used for inorganic compounds like the mono suggest that the atom is only one in the molecule. By this we can get the number of atoms and the answer.
Complete step by step answer:
First of all, all the mentioned compounds are important inorganic compounds and are widely popular and basic level compounds. So now we can say that we have to find the number of the atoms involved according to the atomicity and other factors so that we can get the atoms and then can find the correct example.
So let's do the answer step by step.
-Nitrogen dioxide :
The number of the nitrogen atoms in the molecule are $1$ . As the name itself suggests and the atomicity supports.
The number of the oxygen atoms in the molecule are $2$ . As the name itself suggests (di) and the atomicity supports.
So the formula would be : $N{O_2}$
-Carbon monoxide :
The number of the Carbon atoms in the molecule are $1$ . As the name itself suggests and the atomicity supports.
The number of the oxygen atoms in the molecule are $1$ . As the name itself suggests (mono) and the atomicity supports.
So the formula would be : $CO$
-Oxygen gas :
The number of the oxygen atoms in the molecule are $2$ . As the ture of the gas is diatomic.
So the formula would be : ${O_2}$
-Sulphur dioxide :
The number of the Sulphur atoms in the molecule are $1$ . As the name itself suggests and the atomicity supports.
The number of the oxygen atoms in the molecule are $2$ . As the name itself suggests (di) and the atomicity supports.
So the formula would be : $S{O_2}$
Note:Carbon monoxide is a colorless, odorless, and tasteless flammable gas that is slightly less dense than air. It is toxic to animals that use hemoglobin as an oxygen carrier (both invertebrate and vertebrate) when encountered in concentrations above about \[35{\text{ }}ppm\] , although it is also produced in normal animal metabolism in low quantities, and is thought to have some normal biological functions.
Complete step by step answer:
First of all, all the mentioned compounds are important inorganic compounds and are widely popular and basic level compounds. So now we can say that we have to find the number of the atoms involved according to the atomicity and other factors so that we can get the atoms and then can find the correct example.
So let's do the answer step by step.
-Nitrogen dioxide :
The number of the nitrogen atoms in the molecule are $1$ . As the name itself suggests and the atomicity supports.
The number of the oxygen atoms in the molecule are $2$ . As the name itself suggests (di) and the atomicity supports.
So the formula would be : $N{O_2}$
-Carbon monoxide :
The number of the Carbon atoms in the molecule are $1$ . As the name itself suggests and the atomicity supports.
The number of the oxygen atoms in the molecule are $1$ . As the name itself suggests (mono) and the atomicity supports.
So the formula would be : $CO$
-Oxygen gas :
The number of the oxygen atoms in the molecule are $2$ . As the ture of the gas is diatomic.
So the formula would be : ${O_2}$
-Sulphur dioxide :
The number of the Sulphur atoms in the molecule are $1$ . As the name itself suggests and the atomicity supports.
The number of the oxygen atoms in the molecule are $2$ . As the name itself suggests (di) and the atomicity supports.
So the formula would be : $S{O_2}$
Note:Carbon monoxide is a colorless, odorless, and tasteless flammable gas that is slightly less dense than air. It is toxic to animals that use hemoglobin as an oxygen carrier (both invertebrate and vertebrate) when encountered in concentrations above about \[35{\text{ }}ppm\] , although it is also produced in normal animal metabolism in low quantities, and is thought to have some normal biological functions.
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