
How do you write the chemical equation for the reaction of $\text{NaHC}{{\text{O}}_{3}}$ with $\text{HCl}$?
Answer
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Hint: Chemical reactions are those reactions in which the chemical change is represented by the help of a symbol of an element or the compounds. In chemical reactions, two types of substances are there, the one which reacts during the reaction are called Reactants and the one which forms during the reaction are called Products.
Complete step by step answer:
Chemical change is the change in which reactants react together to form products. During chemical change, either some precipitate forms, gas evolves, colour change.
For example: when Zinc with sulfuric acid liberation of ${{\text{H}}_{\text{2}}}$ gas takes place which represents that some change takes place.
$\text{Zn}+{{\text{H}}_{2}}\text{S}{{\text{o}}_{\text{4}}}\to \text{ZnS}{{\text{o}}_{4}}+{{\text{H}}_{2}}\uparrow $
Step to Step solution: In the question, sodium bi carbonate reacts with $\text{HCl}$ i.e., hydrochloric acid to form sodium chloride, water and evolves $\text{C}{{\text{o}}_{\text{2}}}$ (carbon dioxide)gas.
$\text{NaHC}{{\text{O}}_{\text{3}}}+2\text{HCl}\to \text{NaCl}+{{\text{H}}_{2}}\text{O}+\text{C}{{\text{O}}_{\text{2}}}\uparrow $
The evolution of $\text{C}{{\text{o}}_{\text{2}}}$ can be identified by the lime water The liberated carbon dioxide reacts with calcium hydroxide to form $\text{CaC}{{\text{o}}_{\text{3}}}$ (calcium carbonate)
$\text{Ca(OH}{{\text{)}}_{\text{2}}}\,+\,\text{C}{{\text{o}}_{2}}\to \text{CaC}{{\text{o}}_{3}}+{{\text{H}}_{\text{2}}}\text{O}$
Here milkiness appears due to the formation of calcium carbonate.
Used Chemical equation of $\text{NaHC}{{\text{O}}_{\text{3}}}+\text{HCl}\to \text{NaCl}+{{\text{H}}_{2}}\text{O}+\text{C}{{\text{O}}_{2}}$
Note: The chemical equation can be made more informative by the following ways –
By adding the reaction condition
By adding nature of reactants or products
By adding information about the physical state of reactants and products
By adding the concentration of an acid required during the reaction
By adding the catalyst required for any reaction.
Complete step by step answer:
Chemical change is the change in which reactants react together to form products. During chemical change, either some precipitate forms, gas evolves, colour change.
For example: when Zinc with sulfuric acid liberation of ${{\text{H}}_{\text{2}}}$ gas takes place which represents that some change takes place.
$\text{Zn}+{{\text{H}}_{2}}\text{S}{{\text{o}}_{\text{4}}}\to \text{ZnS}{{\text{o}}_{4}}+{{\text{H}}_{2}}\uparrow $
Step to Step solution: In the question, sodium bi carbonate reacts with $\text{HCl}$ i.e., hydrochloric acid to form sodium chloride, water and evolves $\text{C}{{\text{o}}_{\text{2}}}$ (carbon dioxide)gas.
$\text{NaHC}{{\text{O}}_{\text{3}}}+2\text{HCl}\to \text{NaCl}+{{\text{H}}_{2}}\text{O}+\text{C}{{\text{O}}_{\text{2}}}\uparrow $
The evolution of $\text{C}{{\text{o}}_{\text{2}}}$ can be identified by the lime water The liberated carbon dioxide reacts with calcium hydroxide to form $\text{CaC}{{\text{o}}_{\text{3}}}$ (calcium carbonate)
$\text{Ca(OH}{{\text{)}}_{\text{2}}}\,+\,\text{C}{{\text{o}}_{2}}\to \text{CaC}{{\text{o}}_{3}}+{{\text{H}}_{\text{2}}}\text{O}$
Here milkiness appears due to the formation of calcium carbonate.
Used Chemical equation of $\text{NaHC}{{\text{O}}_{\text{3}}}+\text{HCl}\to \text{NaCl}+{{\text{H}}_{2}}\text{O}+\text{C}{{\text{O}}_{2}}$
Note: The chemical equation can be made more informative by the following ways –
By adding the reaction condition
By adding nature of reactants or products
By adding information about the physical state of reactants and products
By adding the concentration of an acid required during the reaction
By adding the catalyst required for any reaction.
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