Question

Write the chemical equation for the following event: A reaction was brought about between ferric oxide and aluminium.

Answer 1

Hint: We are supposed to write a chemical equation for the given event that reaction was brought between ferric oxide \[\left( {F{e_2}{O_3}} \right)\] and Aluminium $\left( {Al} \right)$. So first try to write the reactants in such a manner that they can be expressed in the form of the chemical equation to give the product.

Complete step by step answer:
First, we will try to understand what a chemical equation is. How it is defined and how we can write the chemical equation.
A chemical equation is defined as the representation of a chemical reaction using chemical formulas and symbols.
Let us understand with the help of a general chemical equation to clear all doubts regarding the chemical equations. So, consider a chemical equation given below,
$A + B \to C + D$
Here, for this chemical equation.
$A,B$ are considered as the reactants of the chemical equation. The left part of a chemical equation is called reactants.
$C,D$ are considered as the product of the chemical equation. The right part of a chemical equation is called a product.
So, now we will try to relate an event given to us with the basics of a chemical equation. We have given that the reaction was brought between ferric oxide \[\left( {F{e_2}{O_3}} \right)\] and Aluminium $\left( {Al} \right)$ . So, the chemical equation for the event can be written as given below,
$F{e_2}{O_3}(s) + 2Al(s)\xrightarrow{\Delta }2Fe(l) + A{l_2}{O_3}(s)$
Here, \[\left( {F{e_2}{O_3}} \right)\] and $\left( {Al} \right)$ are considered as reactants and $(Fe)$ $\left( {A{l_2}{O_3}} \right)$ are considered as products.
Now we will understand how the product is formed. So, consider the above equation,
$F{e_2}{O_3}(s) + 2Al(s)\xrightarrow{\Delta }2Fe(l) + A{l_2}{O_3}(s)$
It is known that aluminium $\left( {Al} \right)$ is more reactive than iron $(Fe)$ . So, according to the concept of reactivity, aluminium metal will replace iron from ferric oxide to form aluminium oxide $\left( {A{l_2}{O_3}} \right)$ and $(Fe)$.
Final result: when the reaction is brought between ferric oxide \[\left( {F{e_2}{O_3}} \right)\] and Aluminium $\left( {Al} \right)$ . The chemical equation for the event can be written as,
$F{e_2}{O_3}(s) + 2Al(s)\xrightarrow{\Delta }2Fe(l) + A{l_2}{O_3}(s)$

Note: For most of the chemical equations the chemical compound present above another chemical compound in the reactivity series will be more reactive and will replace the compound formed with less reactive one.