Write the additive inverse of the complex number of $4-3i$.
Answer
591k+ views
Hint: We here have been given a complex number as $4-3i$ and we need to find its additive inverse. Since it is a complex number, its additive inverse will also be a complex number so we will assume its additive inverse to be a complex number given as $x+iy$ and then we will keep the sum of this assumed complex number and the given complex number equal to 0 and then we will solve that equation. Then we will compare the real and imaginary parts on both the sides of the equal sign and hence obtain the values of x and y. Once we have those, we can obtain the value of the required inverse.
Complete step by step solution:
Now, we know that the additive inverse of a number, whether it be complex or real, is the number which when added to the given number gives 0 as the result.
Here, we have been given a complex number as $4-3i$ whose additive inverse we need to find. For this, we first need to know that the inverse of a complex number is always a complex number and that of a real number is always a real number.
Here, since we have been given a complex number, we will assume the inverse of the given complex number to be another complex number given as $x+iy$. Thus, we can say that:
$\left( 4-3i \right)+\left( x+iy \right)=0$
Now, solving it we get:
$\begin{align}
& \left( 4-3i \right)+\left( x+iy \right)=0 \\
& \Rightarrow x+iy=-4+3i \\
\end{align}$
Now, comparing the real and the imaginary parts of this equation, we get:
$\begin{align}
& x=-4 \\
& y=3 \\
\end{align}$
Thus, putting the values of x and y we get:
$\begin{align}
& x+iy \\
& \therefore -4+3i \\
\end{align}$
Hence, the additive inverse of 4-3i is -4+3i.
Note: We need not assume the complex number in the form of $x+iy$ to solve this question. We can also straightaway assume the inverse to be a complex number ‘z’ and form the equation and directly get the value of z. This is shown as follows:
$\begin{align}
& \left( 4-3i \right)+z=0 \\
& \therefore z=-4+3i \\
\end{align}$
Also, just like real numbers, the additive inverse of a complex number is just the negation of the given complex number.
Complete step by step solution:
Now, we know that the additive inverse of a number, whether it be complex or real, is the number which when added to the given number gives 0 as the result.
Here, we have been given a complex number as $4-3i$ whose additive inverse we need to find. For this, we first need to know that the inverse of a complex number is always a complex number and that of a real number is always a real number.
Here, since we have been given a complex number, we will assume the inverse of the given complex number to be another complex number given as $x+iy$. Thus, we can say that:
$\left( 4-3i \right)+\left( x+iy \right)=0$
Now, solving it we get:
$\begin{align}
& \left( 4-3i \right)+\left( x+iy \right)=0 \\
& \Rightarrow x+iy=-4+3i \\
\end{align}$
Now, comparing the real and the imaginary parts of this equation, we get:
$\begin{align}
& x=-4 \\
& y=3 \\
\end{align}$
Thus, putting the values of x and y we get:
$\begin{align}
& x+iy \\
& \therefore -4+3i \\
\end{align}$
Hence, the additive inverse of 4-3i is -4+3i.
Note: We need not assume the complex number in the form of $x+iy$ to solve this question. We can also straightaway assume the inverse to be a complex number ‘z’ and form the equation and directly get the value of z. This is shown as follows:
$\begin{align}
& \left( 4-3i \right)+z=0 \\
& \therefore z=-4+3i \\
\end{align}$
Also, just like real numbers, the additive inverse of a complex number is just the negation of the given complex number.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

