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Write five pairs of integers (a, b) such that $\dfrac{a}{b}=-3$. One such pair is (6, -2) because $\dfrac{6}{-2}=-3$.

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Hint: We can find pairs by keeping the value of one variable in a given equation and another variable can easily be calculated as it’s just a two-variable equation. Generally, sequential integers are to be used for our ease of understanding.

Complete step-by-step answer:
Here, we have to form such pairs using integers, be it positive or negative, such that $\dfrac{a}{b}=-3$. We can form these pairs by keeping integers on one variable sequentially or randomly, i.e.,
We can start substituting integral values in one variable, let’s say for b

$\dfrac{a}{b}=-3$

Substituting b = 1 in above equation, we get
\[\begin{align}
&\dfrac{a}{b}=-3 \\
&\dfrac{a}{1}=-3 \\
\end{align}\]
On cross-multiplying above equations, we get
 \[a=-3\]

One such pair formed by the values calculated above will be i.e., pair 1: (-3, 1).
Again, substituting sequential or random values for b in the given equation i.e., b = -3, 5, 6, 10, we get
For $b=-3$, we get
\[\begin{align}
&\dfrac{a}{b}=-3 \\
&\dfrac{a}{-3}=-3 \\
\end{align}\]

On cross-multiplying above equations, we get
\[\begin{align}
 &a=\left( -3 \right)\times \left( -3 \right) \\
 &a=9 \\
\end{align}\]

Thus, pairs formed from similar operations in a given equation, we get pair 2: (9, -3).
Similarly, for$b=5$, we get
\[\begin{align}
&\dfrac{a}{b}=-3 \\
&\dfrac{a}{5}=-3 \\
\end{align}\]

On cross-multiplying above equations, we get
\[a=-15\]

Thus, pairs formed from similar operations in a given equation, we get pair 3: (-15, 5).
Now for \[b=6\], we get
\[\begin{align}
&\dfrac{a}{b}=-3 \\
&\dfrac{a}{6}=-3 \\
\end{align}\]

On cross-multiplying above equations, we get
\[a=-18\]

Thus, pairs formed from similar operations in a given equation, we get pair 4: (-18, 6).
Now for \[b=10\], we get
\[\begin{align}
&\dfrac{a}{b}=-3 \\
&\dfrac{a}{10}=-3 \\
\end{align}\]
On cross-multiplying above equations, we get
\[a=-30\]

Thus, pairs formed from similar operations in a given equation, we get pair 5: (-30, 10).
Hence, pairs formed using given conditionality, we get (-3 ,1); (9, -3); (-15, 5); (-18, 6); (-30, 10).

Note: Student might perform a mistake in the sign conventions while substituting values of either a or b in given equation like, \[\dfrac{6}{-2}=\dfrac{-6}{2}=-3\], hence pairs so formed could change from (6, -2) to (-6, 2), unknowingly.
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