Write exponential form for $8 \times 8 \times 8$ taking 2 as base.
Answer
590.4k+ views
Hint: Firstly we have to convert 8 into the exponential form having 2 as base. We already know that the powers of exponents having the same base can be added.
Consider a, b, c be three different numbers then ${a^b} \times {a^c} = {a^{b + c}}$ shall be satisfied.
Complete step-by-step answer:
We all know that 8 can be written as $2 \times 2 \times 2 = {2^3}$.
$
8 \times 8 \times 8 = {2^3} \times {2^3} \times {2^3} \\
= {2^{(3 + 3 + 3)}} \\
= {2^9} \\
$
So the exponential form of $8 \times 8 \times 8$ taking 2 as base is ${2^9}$.
Note: In exponential form we have power and base. Power means the number written in superscript and base is the number written down to power. An exponent denotes the base is multiplied p times (p=power). If two exponents having the same base are divided then their powers are subtracted.
Consider a, b, c be three different numbers then ${a^b} \times {a^c} = {a^{b + c}}$ shall be satisfied.
Complete step-by-step answer:
We all know that 8 can be written as $2 \times 2 \times 2 = {2^3}$.
$
8 \times 8 \times 8 = {2^3} \times {2^3} \times {2^3} \\
= {2^{(3 + 3 + 3)}} \\
= {2^9} \\
$
So the exponential form of $8 \times 8 \times 8$ taking 2 as base is ${2^9}$.
Note: In exponential form we have power and base. Power means the number written in superscript and base is the number written down to power. An exponent denotes the base is multiplied p times (p=power). If two exponents having the same base are divided then their powers are subtracted.
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