
Write any four solutions of the equation x + y = 2.
Answer
616.8k+ views
Hint: In this question simplify x in terms of y. Now since x and y both belong to a set of real numbers as the domain is well defined from ($ - \infty {\text{ to }} + \infty $), so just put the values of y any random from this domain to get x.
Complete step-by-step answer:
Given linear equation is
$x + y = 2$................... (1)
We have to write any four solutions to this equation.
So from equation (1)
$x = \left( {2 - y} \right)$...................... (2)
As we know y can be anything from ($ - \infty {\text{ to }} + \infty $) but here we have to find only four solutions.
So let y = (1, 2, 3 and 4)
So for y = 1
From equation (2)
$x = 2 - 1 = 1$
So the first solution is (1, 1)
For y = 2
From equation (2)
$x = 2 - 2 = 0$
So the second solution is (0, 2)
For y = 3
From equation (2)
$x = 2 - 3 = - 1$
So the third solution is (-1, 3)
For y = 4
From equation (2)
$x = 2 - 4 = - 2$
So the forth solution is (-2, 4)
So these are the required four solutions of the given equation.
So this is the required answer.
Note: The domain of function is defined as the values at which the function is defined and the range refers to the all possible set of output which the function yields when its domain is substituted into it. For example, if we have $y = {x^2}$, the domain is the value of x for which it is defined so it is set of real numbers, however the range is all set of positive real numbers as a square can’t produce a negative entity. If we look at the graph of it then the x axis denotes domain and y as range.
Complete step-by-step answer:
Given linear equation is
$x + y = 2$................... (1)
We have to write any four solutions to this equation.
So from equation (1)
$x = \left( {2 - y} \right)$...................... (2)
As we know y can be anything from ($ - \infty {\text{ to }} + \infty $) but here we have to find only four solutions.
So let y = (1, 2, 3 and 4)
So for y = 1
From equation (2)
$x = 2 - 1 = 1$
So the first solution is (1, 1)
For y = 2
From equation (2)
$x = 2 - 2 = 0$
So the second solution is (0, 2)
For y = 3
From equation (2)
$x = 2 - 3 = - 1$
So the third solution is (-1, 3)
For y = 4
From equation (2)
$x = 2 - 4 = - 2$
So the forth solution is (-2, 4)
So these are the required four solutions of the given equation.
So this is the required answer.
Note: The domain of function is defined as the values at which the function is defined and the range refers to the all possible set of output which the function yields when its domain is substituted into it. For example, if we have $y = {x^2}$, the domain is the value of x for which it is defined so it is set of real numbers, however the range is all set of positive real numbers as a square can’t produce a negative entity. If we look at the graph of it then the x axis denotes domain and y as range.
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