
How do you write a system of equations with the solution \[\left( {4, - 3} \right)\]?
Answer
541.8k+ views
Hint: Here, we will substitute different values in the coefficients of \[x\] and \[y\] to find two equations out of infinitely many equations with this particular solution. Substituting \[\left( {x,y} \right)\] as \[\left( {4, - 3} \right)\], we will be able to find the constant of these equations and by substituting them, we will be able to find the required system of equations.
Complete step-by-step answers:
In order to write a system of equations with the solution \[\left( {4, - 3} \right)\], we should know that there are infinitely many equations having this particular solution.
Thus, as we know that the standard form of a linear equation in two variables is \[ax + by + c = 0\] or \[ax + by = - c\], we will choose any coefficients for \[x\] and \[y\] and try to make two equations keeping in mind that the coefficients are not proportional.
Thus, let \[a = 1\] and \[b = 2\]
Hence, we get the first equation as:
\[1x + 2y = c\]
And for the second equation let the coefficients \[a,b\] be equal to \[3,4\] respectively.
Thus, we get,
\[3x + 4y = k\]
Now, since, the solution of these equations should be \[\left( {4, - 3} \right)\]
Hence, substituting \[x = 4\] and \[y = - 3\] in \[1x + 2y = c\], we get,
\[\left( 1 \right)\left( 4 \right) + 2\left( { - 3} \right) = c\]
Multiplying the terms, we get
\[\begin{array}{l} \Rightarrow 4 - 6 = c\\ \Rightarrow - 2 = c\end{array}\]
Hence, the first equation is:
\[x + 2y = - 2\]
Now, substituting \[x = 4\] and \[y = - 3\] in \[3x + 4y = k\], we get,
\[3\left( 4 \right) + 4\left( { - 3} \right) = k\]
Multiplying the terms, we get
\[\begin{array}{l} \Rightarrow 12 - 12 = k\\ \Rightarrow 0 = k\end{array}\]
Hence, the first equation is:
\[3x + 4y = 0\]
Therefore, these are two systems of equations which are having the solution \[\left( {4, - 3} \right)\]
By assuming various values of the coefficients of \[x\] and \[y\], we can find infinitely many systems of equations having this solution.
Note:
An equation is called linear equation in two variables if it can be written in the form of \[ax + by + c = 0\] where \[a,b,c\] are real numbers and \[a \ne 0\] , \[b \ne 0\] as they are coefficients of \[x\] and \[y\] respectively. Also, the power of linear equations in two variables will be 1 as it is a ‘linear equation’. Also, a linear equation in two variables can sometimes have infinitely many solutions rather than only one in the case of ‘one variable’.
Complete step-by-step answers:
In order to write a system of equations with the solution \[\left( {4, - 3} \right)\], we should know that there are infinitely many equations having this particular solution.
Thus, as we know that the standard form of a linear equation in two variables is \[ax + by + c = 0\] or \[ax + by = - c\], we will choose any coefficients for \[x\] and \[y\] and try to make two equations keeping in mind that the coefficients are not proportional.
Thus, let \[a = 1\] and \[b = 2\]
Hence, we get the first equation as:
\[1x + 2y = c\]
And for the second equation let the coefficients \[a,b\] be equal to \[3,4\] respectively.
Thus, we get,
\[3x + 4y = k\]
Now, since, the solution of these equations should be \[\left( {4, - 3} \right)\]
Hence, substituting \[x = 4\] and \[y = - 3\] in \[1x + 2y = c\], we get,
\[\left( 1 \right)\left( 4 \right) + 2\left( { - 3} \right) = c\]
Multiplying the terms, we get
\[\begin{array}{l} \Rightarrow 4 - 6 = c\\ \Rightarrow - 2 = c\end{array}\]
Hence, the first equation is:
\[x + 2y = - 2\]
Now, substituting \[x = 4\] and \[y = - 3\] in \[3x + 4y = k\], we get,
\[3\left( 4 \right) + 4\left( { - 3} \right) = k\]
Multiplying the terms, we get
\[\begin{array}{l} \Rightarrow 12 - 12 = k\\ \Rightarrow 0 = k\end{array}\]
Hence, the first equation is:
\[3x + 4y = 0\]
Therefore, these are two systems of equations which are having the solution \[\left( {4, - 3} \right)\]
By assuming various values of the coefficients of \[x\] and \[y\], we can find infinitely many systems of equations having this solution.
Note:
An equation is called linear equation in two variables if it can be written in the form of \[ax + by + c = 0\] where \[a,b,c\] are real numbers and \[a \ne 0\] , \[b \ne 0\] as they are coefficients of \[x\] and \[y\] respectively. Also, the power of linear equations in two variables will be 1 as it is a ‘linear equation’. Also, a linear equation in two variables can sometimes have infinitely many solutions rather than only one in the case of ‘one variable’.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which places in India experience sunrise first and class 9 social science CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Write the 6 fundamental rights of India and explain in detail

Difference Between Plant Cell and Animal Cell

What is pollution? How many types of pollution? Define it

What is the full form of pH?


