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Write a balanced equation for the reaction of \[KH\] with water
A. \[KH + {H_2}O \to {\text{ }}KOH + {H_2}{O_2}\]
B. \[KH + {H_2}O \to {\text{ }}KOH + {H_2}\]
C. \[KH + {H_2}O \to {\text{ }}K{(OH)_2} + {H_2}{O_2}\]
D. \[KH + {H_2}O \to {\text{ }}KOH + {H_2}O\]

Answer
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Hint:To answer this question, you should recall the concept of balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products. This is important because a chemical equation must obey the law of conservation of mass and the law of constant proportions.

Complete answer:
We know that a chemical equation is a symbolic representation of a chemical reaction in which the reactants and products are denoted by their respective chemical formulae. The reactant side is the part of the chemical equation to the left of the arrow symbol whereas the product side is the part to the right of the arrow symbol. Potassium hydride hydrolysis in water to form hydroxide.
The reaction can be represented by the equation:
 \[KH + {H_2}O \to {\text{ }}KOH + {H_2}\]

Hence, option B is correct.

Note:
In Algebra the Coefficient is the number in front of the variable terms. In any type of chemical equation, there are two types of numbers. They are subscripts and coefficients. Subscripts are defined as a part of the chemical formulas of the reactants and products and the other type talked above are coefficients that are placed in front of the formulas to indicate how many molecules of that substance is used or produced. While the other type coefficients indicate the number of each substance involved in the reaction and may be changed to balance the equation. In the Haber’s process equation for Ammonia \[{N_2} + 3{H_2} \to 2N{H_3}\] .
Here we can see that coefficients of: 1 for \[{N_2}\] , 3 for \[{H_2}\] and 2 for \[N{H_3}\] . The reaction shows that each cycle of the forward reaction involves 1 molecule of \[{N_2}\] with 3 molecules \[{H_2}\] to produce 2 molecules of \[N{H_3}\] . Subscripts in the reaction cannot be changed.