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# How do you write 7 less than the product of two numbers?

Last updated date: 24th Jul 2024
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Hint: We first try to make the given written statement in its mathematical form. We assume two variables $m$ and $n$ for the multiplication. Then we multiply those terms. We follow the multiplication process for signs and find the right sign for the multiplication. Then we need to subtract 7 from the multiplied value. We get the mathematical statement as the solution.

The given statement is that we need to find the mathematical form of the expression which is 7 less than the product of two numbers.
We first assume those two numbers as variable. Let those numbers be $m$ and $n$ for the multiplication.
We need to find the multiplied value of those numbers which is $m\times n=mn$.
We can express the signs in this way $\left( - \right)\times \left( + \right)=\left( - \right)$ and $\left( - \right)\times \left( - \right)=\left( + \right)$.
We follow the multiplication process for signs and find the right sign for the multiplication.
Now we need 7 less than the product of two numbers.
That’s why we subtract 7 from the product value of $mn$.
The final solution is $\left( mn-7 \right)$.

Therefore, the final algebraic expression of 7 less than the product of two numbers is $\left( mn-7 \right)$.

Note: we can verify the result by taking two values for $m$ and $n$ for the multiplication. We take $m=2$ and $n=1$.
We have to find the subtracted form of $\left( mn-7 \right)$.
This gives $\left( mn-7 \right)=2\times 1-7=2-7=-5$.