
Why is \[Pb{{O}_{2}}\] not peroxide?
Answer
494.1k+ views
Hint: Peroxide ion has the molecular formula \[{{O}_{2}}^{2-}\]. The treatment of metallic oxides with acid i.e. hydrochloric acid produces hydrogen peroxide. The formation of peroxides is feasible with hydrogen, alkali and alkaline earth metals.
Complete answer:
Peroxides are formed by the treatment of metallic oxides with acid i.e. hydrochloric acid. The molecular formula of peroxide ion is \[{{O}_{2}}^{2-}\]. The structure of hydrogen peroxide is given in the following diagram:
From the above diagram, we conclude that in peroxides, there is a single bond present between two oxygen atoms and charge on each oxygen atom is \[-1\]. Let us now consider the structure of \[Pb{{O}_{2}}\] which is described in the following diagram-
From the above structure, we conclude that \[O-O\]bond is not present in \[Pb{{O}_{2}}\] . In \[Pb{{O}_{2}}\] , lead is present in \[+4\] oxidation state while each oxygen atom carries a \[-2\] charge.
Therefore, \[Pb{{O}_{2}}\] is not a peroxide.
Additional information:
The chemical name of \[Pb{{O}_{2}}\] is lead dioxide. The electronic configuration of lead is \[[Xe]6{{s}^{2}}4{{f}^{14}}5{{d}^{10}}6{{p}^{2}}\]. Considering the electronic configuration into the account, the oxidation state of lead should be \[+2\] and \[+4\]. Due to the inert pair effect, \[+2\]oxidation state of lead is more stable in comparison to \[+4\] . As a consequence, \[PbO\] is much more stable than \[Pb{{O}_{2}}\].
Note:
It is important to note that the structure of \[Pb{{O}_{2}}\] doesn’t contain \[O-O\] bond. Hence, \[Pb{{O}_{2}}\] is not a peroxide. In \[Pb{{O}_{2}}\] , lead is present in \[+4\] oxidation state while each oxygen atom carries a \[-2\] charge.
Complete answer:
Peroxides are formed by the treatment of metallic oxides with acid i.e. hydrochloric acid. The molecular formula of peroxide ion is \[{{O}_{2}}^{2-}\]. The structure of hydrogen peroxide is given in the following diagram:
From the above diagram, we conclude that in peroxides, there is a single bond present between two oxygen atoms and charge on each oxygen atom is \[-1\]. Let us now consider the structure of \[Pb{{O}_{2}}\] which is described in the following diagram-
From the above structure, we conclude that \[O-O\]bond is not present in \[Pb{{O}_{2}}\] . In \[Pb{{O}_{2}}\] , lead is present in \[+4\] oxidation state while each oxygen atom carries a \[-2\] charge.
Therefore, \[Pb{{O}_{2}}\] is not a peroxide.
Additional information:
The chemical name of \[Pb{{O}_{2}}\] is lead dioxide. The electronic configuration of lead is \[[Xe]6{{s}^{2}}4{{f}^{14}}5{{d}^{10}}6{{p}^{2}}\]. Considering the electronic configuration into the account, the oxidation state of lead should be \[+2\] and \[+4\]. Due to the inert pair effect, \[+2\]oxidation state of lead is more stable in comparison to \[+4\] . As a consequence, \[PbO\] is much more stable than \[Pb{{O}_{2}}\].
Note:
It is important to note that the structure of \[Pb{{O}_{2}}\] doesn’t contain \[O-O\] bond. Hence, \[Pb{{O}_{2}}\] is not a peroxide. In \[Pb{{O}_{2}}\] , lead is present in \[+4\] oxidation state while each oxygen atom carries a \[-2\] charge.
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