Why is \[Cu{I_2}\] unstable?
Answer
526.5k+ views
Hint: Any chemical compound is stable in nature if it is present in its most common oxidation number. Different compounds show reducing power and oxidizing power depending upon their position in electrochemical series.
Complete answer:
Electrochemical series contain large numbers of elements which are organized in a sequence of their oxidizing power and reducing power. When we look into the series, we find that the conversion of ${I_2} \to {I^ - }$ lies above the conversion of $C{u^{ + 2}} \to Cu$.
But when we reverse the conversion of ${I_2} \to {I^ - }$ into ${I^ - } \to {I_2}$, iodide ion acts as a strong reducing agent and has tendency to convert $C{u^{ + 2}} \to C{u^ + }$.
Elements which lie atop of the electrochemical series have high value of electrode potential and therefore they easily undergo reduction and act as a good excellent oxidizing agent.
When $C{u^{ + 2}}$ ions reacts with ${I^ - }$ ions to form the compound \[Cu{I_2}\].
Redox reaction between ions is expressed as:
$C{u^{ + 2}}$$ + $${I^ - }$$ \to $$Cu{I_2}$
In the above reaction we see that iodide ions get converted into iodine and hence, a process of oxidation takes place.
But from the above discussion we already see that conversion of ${I_2} \to {I^ - }$ is more stable according to the electrochemical series. Therefore, formation of $Cu{I_2}$ is not preferred instead of which another halide of copper is formed which is stable in nature.
The redox reaction to from stable compound is expressed as-
${I_{2\left( {aq} \right)}} + 2C{u^ + }_{\left( {aq} \right)} \to 2Cu{I_{\left( S \right)}}$
$ \Rightarrow $ \[Cu{I_2}\] is unstable in nature because iodide ion act as very good reducing agent and it promote conversion of cupric ion $C{u^{ + 2}}$ into cuprous ion $C{u^ + }$ which further form stable compound $CuI$.
Note:
Electrochemical series also help us to determine the chances of feasibility of the redox reaction. According to the series the chemical reaction is feasible only if compounds with higher reduction potential get reduced during the reaction.
Complete answer:
Electrochemical series contain large numbers of elements which are organized in a sequence of their oxidizing power and reducing power. When we look into the series, we find that the conversion of ${I_2} \to {I^ - }$ lies above the conversion of $C{u^{ + 2}} \to Cu$.
But when we reverse the conversion of ${I_2} \to {I^ - }$ into ${I^ - } \to {I_2}$, iodide ion acts as a strong reducing agent and has tendency to convert $C{u^{ + 2}} \to C{u^ + }$.
Elements which lie atop of the electrochemical series have high value of electrode potential and therefore they easily undergo reduction and act as a good excellent oxidizing agent.
When $C{u^{ + 2}}$ ions reacts with ${I^ - }$ ions to form the compound \[Cu{I_2}\].
Redox reaction between ions is expressed as:
$C{u^{ + 2}}$$ + $${I^ - }$$ \to $$Cu{I_2}$
In the above reaction we see that iodide ions get converted into iodine and hence, a process of oxidation takes place.
But from the above discussion we already see that conversion of ${I_2} \to {I^ - }$ is more stable according to the electrochemical series. Therefore, formation of $Cu{I_2}$ is not preferred instead of which another halide of copper is formed which is stable in nature.
The redox reaction to from stable compound is expressed as-
${I_{2\left( {aq} \right)}} + 2C{u^ + }_{\left( {aq} \right)} \to 2Cu{I_{\left( S \right)}}$
$ \Rightarrow $ \[Cu{I_2}\] is unstable in nature because iodide ion act as very good reducing agent and it promote conversion of cupric ion $C{u^{ + 2}}$ into cuprous ion $C{u^ + }$ which further form stable compound $CuI$.
Note:
Electrochemical series also help us to determine the chances of feasibility of the redox reaction. According to the series the chemical reaction is feasible only if compounds with higher reduction potential get reduced during the reaction.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

