Which term of the A.P $150$ , $147$ , $144$ ,…… is its first negative term?
Answer
547.8k+ views
Hint: In this problem we need to find which term of the given A.P is the first negative term. So we will first consider the given A.P and compare it with ${{a}_{0}}$ , ${{a}_{1}}$ , ${{a}_{2}}$ ,….. and calculate the value of common difference $d$ which is given by ${{a}_{1}}-{{a}_{0}}$ or ${{a}_{2}}-{{a}_{1}}$ . Now we will first check whether the given A.P has a zero value or not by using the formula ${{a}_{n}}={{a}_{0}}+\left( n-1 \right)d$ . In this formula we will substitute ${{a}_{n}}=0$ and calculate the value of $n$ by using basic mathematical operations. If we get the $n$value as a natural number, then the upcoming term in the A.P is the first negative term.
Complete step by step answer:
Given Arithmetic Progression is $150$ , $147$ , $144$ ,……
Comparing the above Arithmetic Progression with ${{a}_{0}}$ , ${{a}_{1}}$ , ${{a}_{2}}$ ,….., then we will have
${{a}_{0}}=150$ , ${{a}_{1}}=147$ , ${{a}_{2}}=144$ .
Now the common difference $d$ of the progression is equal to the difference between the two successive terms, then we will get
$\begin{align}
& d={{a}_{1}}-{{a}_{0}}\text{ or }{{a}_{2}}-{{a}_{1}} \\
& \Rightarrow d=147-150\,\text{ or }144-147 \\
& \Rightarrow d=-3 \\
\end{align}$
We are going to check whether the given Arithmetic Progression has $0$ or not by substituting ${{a}_{n}}=0$ in the formula ${{a}_{n}}={{a}_{0}}+\left( n-1 \right)d$, then we will get
$0=150+\left( n-1 \right)\left( -3 \right)$
Simplifying the above equation by applying basic mathematical operations, then we will have
$\begin{align}
& 0=150-\left( n-1 \right)3 \\
& \Rightarrow 3\left( n-1 \right)=150 \\
& \Rightarrow n-1=\dfrac{150}{3} \\
& \Rightarrow n=50+1 \\
& \Rightarrow n=51 \\
\end{align}$
From the above value we can say that ${{51}^{st}}$ term of the given Arithmetic Progression is zero. So the next term which is ${{52}^{nd}}\left( 51+1 \right)$ terms is definitely the first negative term of the given Arithmetic Progression.
Note: In this problem when we are checking whether the given progression has zero or not. We have the value of $n$ as $51$ which is a natural number. There is no guarantee that each progression has zero or for each progression we can get the value of $n$as a natural number. In some cases we may get a fraction also. In that case we will consider $n$value to the nearest natural number and check whether it is a negative number or not.
Complete step by step answer:
Given Arithmetic Progression is $150$ , $147$ , $144$ ,……
Comparing the above Arithmetic Progression with ${{a}_{0}}$ , ${{a}_{1}}$ , ${{a}_{2}}$ ,….., then we will have
${{a}_{0}}=150$ , ${{a}_{1}}=147$ , ${{a}_{2}}=144$ .
Now the common difference $d$ of the progression is equal to the difference between the two successive terms, then we will get
$\begin{align}
& d={{a}_{1}}-{{a}_{0}}\text{ or }{{a}_{2}}-{{a}_{1}} \\
& \Rightarrow d=147-150\,\text{ or }144-147 \\
& \Rightarrow d=-3 \\
\end{align}$
We are going to check whether the given Arithmetic Progression has $0$ or not by substituting ${{a}_{n}}=0$ in the formula ${{a}_{n}}={{a}_{0}}+\left( n-1 \right)d$, then we will get
$0=150+\left( n-1 \right)\left( -3 \right)$
Simplifying the above equation by applying basic mathematical operations, then we will have
$\begin{align}
& 0=150-\left( n-1 \right)3 \\
& \Rightarrow 3\left( n-1 \right)=150 \\
& \Rightarrow n-1=\dfrac{150}{3} \\
& \Rightarrow n=50+1 \\
& \Rightarrow n=51 \\
\end{align}$
From the above value we can say that ${{51}^{st}}$ term of the given Arithmetic Progression is zero. So the next term which is ${{52}^{nd}}\left( 51+1 \right)$ terms is definitely the first negative term of the given Arithmetic Progression.
Note: In this problem when we are checking whether the given progression has zero or not. We have the value of $n$ as $51$ which is a natural number. There is no guarantee that each progression has zero or for each progression we can get the value of $n$as a natural number. In some cases we may get a fraction also. In that case we will consider $n$value to the nearest natural number and check whether it is a negative number or not.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

