Which reagent is used to convert \[2-\]butanone into propanoic acid?
A.\[NaOH,{{I}_{2}}/{{H}^{+}}~\]
B.Tollen’s reagent.
C.Fehling's solution.
D.\[NaOH,NaI/{{H}^{+}}~\]
Answer
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Hint: We know that the propanoic acid is converted into ethanol by reduction and then this ethanol on oxidation gives ethyl aldehyde. This is converted to \[2-\]ethyl \[2-\]ethanol which on further oxidation gives us the desired product Butan\[-2-\]one.
Complete step by step answer:
To form butanone from calcium salt of fatty acids the decomposition process takes place of calcium acetate and calcium propionate. In the products formed calcium carbonate formation takes place as a byproduct. In this the two compounds calcium acetate and calcium propionate react together under conditions of heating and dry distillation to form butanone the main product and white precipitate of calcium carbonate.
Haloform reagent, \[NaOH,{{I}_{2}}/{{H}^{+}}~\] in acidic medium form the iodoform and acidic compound.
Hence \[NaOH,{{I}_{2}}/{{H}^{+}}~\]can be used to convert \[2-\]butanone into propanoic acid.
Therefore, the correct answer is option A.
Additional Information:
Butanone is also formed by the oxidation of \[2-\]butanol. The \[2-\]butanone is a colorless liquid with sharp and sweet odour. It can be manufactured but it is also present in the environment naturally. It is also known as MEK which is methyl ethyl ketone, a flammable liquid compound. The pH value for MEK is $5.5.$it is used to remove all types of paints and can be used as seam sealers. It has a good ability to evaporate and does nothing to rust.
Note:
Remember that MEK is used in all types of industries such as in military outfits aerospace giants. It has good cleaning power and has the ability to dissolve any tough residue. It was banned in California in \[2011.\] It is one of the best solvent thin contact cement when it is used to attach plastic covering.
Complete step by step answer:
To form butanone from calcium salt of fatty acids the decomposition process takes place of calcium acetate and calcium propionate. In the products formed calcium carbonate formation takes place as a byproduct. In this the two compounds calcium acetate and calcium propionate react together under conditions of heating and dry distillation to form butanone the main product and white precipitate of calcium carbonate.
Haloform reagent, \[NaOH,{{I}_{2}}/{{H}^{+}}~\] in acidic medium form the iodoform and acidic compound.
Hence \[NaOH,{{I}_{2}}/{{H}^{+}}~\]can be used to convert \[2-\]butanone into propanoic acid.
Therefore, the correct answer is option A.
Additional Information:
Butanone is also formed by the oxidation of \[2-\]butanol. The \[2-\]butanone is a colorless liquid with sharp and sweet odour. It can be manufactured but it is also present in the environment naturally. It is also known as MEK which is methyl ethyl ketone, a flammable liquid compound. The pH value for MEK is $5.5.$it is used to remove all types of paints and can be used as seam sealers. It has a good ability to evaporate and does nothing to rust.
Note:
Remember that MEK is used in all types of industries such as in military outfits aerospace giants. It has good cleaning power and has the ability to dissolve any tough residue. It was banned in California in \[2011.\] It is one of the best solvent thin contact cement when it is used to attach plastic covering.
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