
Which reaction sequence would be best to prepare 3-chloroaniline from benzene?
A.Chlorination, Nitration, Reduction
B.Nitration, Chlorination, Reduction
C.Nitration, Reduction, Chlorination
D.Nitration, Reduction, Acetylation, chlorination, hydrolysis
Answer
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Hint: The nitro group is added in the benzene ring to form the nitrobenzene. Then, nitro benzene is treated with ferric chloride. Since the nitro group is a meta director, we can add Chlorine (Cl) through chlorination. After that, we can reduce the \[N{O_2}\] Group to \[N{H_2}\] Group.
Complete answer:
First we add nitro group (\[N{O_2}\]) to the benzene ring to form nitrobenzene through nitration of benzene as nitration of benzene will give nitro benzene as a product. Then, we will treat nitro benzene with ferric chloride in the presence of chlorine gas which will give 3- chloro nitro benzene. In the last step, the reduction of nitro group in 3-chloro nitro benzene by lithium aluminium hydride which will give us 3-chloro aniline.
Since the nitro group is a meta director, we can then add Cl through chlorination. After that, we can reduce the \[N{O_2}\] Group to \[N{H_2}\] Group.
Here’s a possible synthesis we can consider:
So, the correct reaction sequence that is best to prepare 3-chloroaniline from benzene is Nitration, Chlorination, Reduction.
Therefore, the correct answer is option (B).
Note: An alternative we can consider to prepare 3-chloroaniline from benzene is:
This synthesis involves adding two substituents to the benzene ring. In this case, we need to consider the order of substitution. Cl is an ortho-para director. That means, if Cl is first added to the benzene, the next substituent will be placed in the ortho/para position and that will not work since, in the desired product, \[N{H_2}\] is meta to Cl. That means, we need to add Cl in the last. \[N{H_2}\] is also an ortho-para director, so that means we can’t add Cl after forming aniline.
3-Nitrochlorobenzene is an organic compound with the formula \[{C_6}{H_4}ClN{O_2}\]. It is a yellow crystalline solid that is important as a precursor to other compounds due to the two reactive sites present on the molecule.
Complete answer:
First we add nitro group (\[N{O_2}\]) to the benzene ring to form nitrobenzene through nitration of benzene as nitration of benzene will give nitro benzene as a product. Then, we will treat nitro benzene with ferric chloride in the presence of chlorine gas which will give 3- chloro nitro benzene. In the last step, the reduction of nitro group in 3-chloro nitro benzene by lithium aluminium hydride which will give us 3-chloro aniline.
Since the nitro group is a meta director, we can then add Cl through chlorination. After that, we can reduce the \[N{O_2}\] Group to \[N{H_2}\] Group.
Here’s a possible synthesis we can consider:
So, the correct reaction sequence that is best to prepare 3-chloroaniline from benzene is Nitration, Chlorination, Reduction.
Therefore, the correct answer is option (B).
Note: An alternative we can consider to prepare 3-chloroaniline from benzene is:
This synthesis involves adding two substituents to the benzene ring. In this case, we need to consider the order of substitution. Cl is an ortho-para director. That means, if Cl is first added to the benzene, the next substituent will be placed in the ortho/para position and that will not work since, in the desired product, \[N{H_2}\] is meta to Cl. That means, we need to add Cl in the last. \[N{H_2}\] is also an ortho-para director, so that means we can’t add Cl after forming aniline.
3-Nitrochlorobenzene is an organic compound with the formula \[{C_6}{H_4}ClN{O_2}\]. It is a yellow crystalline solid that is important as a precursor to other compounds due to the two reactive sites present on the molecule.
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