
Which one of the following represents the vertex form of a quadratic function?
(a) \[f\left( x \right)=a{{x}^{2}}+bx+c\]
(b) \[f\left( x \right)=a{{\left( x-h \right)}^{2}}+k\]
(c) \[f\left( x \right)=\left( x-{{x}_{1}} \right)\cdot \left( x-{{x}_{2}} \right)\]
(d) none of these
Answer
543.9k+ views
Hint: We start solving the problem by recalling the fact that the quadratic equation resembles the equation of parabola with axis parallel to y-axis. We then recall the equation of the parabola with vertex at $\left( h,k \right)$ and the axis parallel to y-axis is $a{{\left( x-h \right)}^{2}}=y-k$. We then make the necessary calculations to find the equation resembling $y=f\left( x \right)$. We then replace y with $f\left( x \right)$ to find the required form of the quadratic function.
Complete step by step solution:
According to the problem, we need to find the vertex form of a quadratic function.
We know that the quadratic equation resembles the equation of parabola with an axis parallel to the y-axis.
We know that the equation of the parabola with vertex at $\left( h,k \right)$ and axis parallel to y-axis is $a{{\left( x-h \right)}^{2}}=y-k$.
Now, we have $y=a{{\left( x-h \right)}^{2}}+k$.
As we can see that the polynomial on the right-hand side resembles the quadratic equation. So, let us assume $y=f\left( x \right)$.
$\Rightarrow f\left( x \right)=a{{\left( x-h \right)}^{2}}+k$, which is the vertex form of the required quadratic equation.
So, we have found the vertex form of a quadratic equation as $f\left( x \right)=a{{\left( x-h \right)}^{2}}+k$.
So, the correct answer is “Option B”.
Note: We should know that the quadratic equation will be of the form $a{{x}^{2}}+bx+c=0$ which resembles the equation of parabola with axis parallel to zero when the value of ‘y’ is set equal to 0. We should that the equation $f\left( x \right)=\left( x-{{x}_{1}} \right).\left( x-{{x}_{2}} \right)$ is known as the two-point form of the quadratic function. Since the given problem has asked about the quadratic function not about the quadratic equation, we do not equate it to zero.
Complete step by step solution:
According to the problem, we need to find the vertex form of a quadratic function.
We know that the quadratic equation resembles the equation of parabola with an axis parallel to the y-axis.
We know that the equation of the parabola with vertex at $\left( h,k \right)$ and axis parallel to y-axis is $a{{\left( x-h \right)}^{2}}=y-k$.
Now, we have $y=a{{\left( x-h \right)}^{2}}+k$.
As we can see that the polynomial on the right-hand side resembles the quadratic equation. So, let us assume $y=f\left( x \right)$.
$\Rightarrow f\left( x \right)=a{{\left( x-h \right)}^{2}}+k$, which is the vertex form of the required quadratic equation.
So, we have found the vertex form of a quadratic equation as $f\left( x \right)=a{{\left( x-h \right)}^{2}}+k$.
So, the correct answer is “Option B”.
Note: We should know that the quadratic equation will be of the form $a{{x}^{2}}+bx+c=0$ which resembles the equation of parabola with axis parallel to zero when the value of ‘y’ is set equal to 0. We should that the equation $f\left( x \right)=\left( x-{{x}_{1}} \right).\left( x-{{x}_{2}} \right)$ is known as the two-point form of the quadratic function. Since the given problem has asked about the quadratic function not about the quadratic equation, we do not equate it to zero.
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