
Which one of the following orders is not in accordance with the property stated against it?
A. ${{F}_{2}}$ > $C{{l}_{2}}$ > Br > ${{I}_{2}}$ : Electronegativity
B. ${{F}_{2}}$ > $C{{l}_{2}}$ > $B{{r}_{2}}$ > ${{I}_{2}}$ : Bond dissociation energy
C. ${{F}_{2}}$ > $C{{l}_{2}}$ > $B{{r}_{2}}$ > ${{I}_{2}}$ : Oxidizing power
D. HI > HBr > HCl > HF: acidic property in water
Answer
517.5k+ views
Hint: The electronegativity of the elements which are present in the periodic table is going to decrease when we are moving from top to bottom in the periodic table. The oxidizing power of the elements also decreases while moving from top to bottom in the periodic table.
Complete answer:
- In the question it is given that to find the wrong option among the given options.
- We have to find the option which is not in accordance with the property stated beside it.
- Coming to given options, option A, ${{F}_{2}}$ > $C{{l}_{2}}$ > Br > ${{I}_{2}}$ : Electronegativity.
- We know that the electronegativity of the halogens is going to decrease as we are moving to top to bottom in the periodic table. so, the statement A is correct.
- Coming to option B, ${{F}_{2}}$ > $C{{l}_{2}}$ > $B{{r}_{2}}$ > ${{I}_{2}}$ : Bond dissociation energy.
- The option B is wrong because the correct order of bond dissociation energy of the halogens is $C{{l}_{2}}$ >$B{{r}_{2}}$ > ${{F}_{2}}$ > ${{I}_{2}}$.
- Therefore option B is incorrect.
- Coming to option C, ${{F}_{2}}$ > $C{{l}_{2}}$ > $B{{r}_{2}}$ > ${{I}_{2}}$ : Oxidizing power. It is correct because fluorine has high electronegativity so the oxidizing power of fluorine is high when compared to remaining halogens.
- Coming to option D, HI > HBr > HCl > HF: acidic property in water. It is also correct because the acidity of the hydrogen halides is going to decrease in the order of HI > HBr > HCl > HF.
- Therefore the order is not in accordance with the property stated against it is option B.
So, the correct option is C.
Note:
The amount of energy required to break a bond in a molecule is called bond dissociation energy. The hydrogen halides are acidic in nature and the acidity of the hydrogen halides are going to decrease with increase in electronegativity of the halogen.
Complete answer:
- In the question it is given that to find the wrong option among the given options.
- We have to find the option which is not in accordance with the property stated beside it.
- Coming to given options, option A, ${{F}_{2}}$ > $C{{l}_{2}}$ > Br > ${{I}_{2}}$ : Electronegativity.
- We know that the electronegativity of the halogens is going to decrease as we are moving to top to bottom in the periodic table. so, the statement A is correct.
- Coming to option B, ${{F}_{2}}$ > $C{{l}_{2}}$ > $B{{r}_{2}}$ > ${{I}_{2}}$ : Bond dissociation energy.
- The option B is wrong because the correct order of bond dissociation energy of the halogens is $C{{l}_{2}}$ >$B{{r}_{2}}$ > ${{F}_{2}}$ > ${{I}_{2}}$.
- Therefore option B is incorrect.
- Coming to option C, ${{F}_{2}}$ > $C{{l}_{2}}$ > $B{{r}_{2}}$ > ${{I}_{2}}$ : Oxidizing power. It is correct because fluorine has high electronegativity so the oxidizing power of fluorine is high when compared to remaining halogens.
- Coming to option D, HI > HBr > HCl > HF: acidic property in water. It is also correct because the acidity of the hydrogen halides is going to decrease in the order of HI > HBr > HCl > HF.
- Therefore the order is not in accordance with the property stated against it is option B.
So, the correct option is C.
Note:
The amount of energy required to break a bond in a molecule is called bond dissociation energy. The hydrogen halides are acidic in nature and the acidity of the hydrogen halides are going to decrease with increase in electronegativity of the halogen.
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