
Which one of the following is the unit of compressibility?
A.\[{{m}^{3/}}N\]
B.\[{{m}^{2}}/N\]
C.\[{{m}^{2}}-N\]
D.\[m/N\]
Answer
584.4k+ views
Hint: Compressibility is the property of being decreased to a smaller space by pressure. This property is a result of porosity, and the difference in mass originates from the particles being united by the weight.
Complete answer:
Compressibility is the proportional of bulk modulus of flexibility (k). Bulk modulus is characterized as the proportion of compressive worry to the volumetric strain.
Consider a chamber loaded up with liquid and shut by cylinder when cylinder push ahead and pressure increment yet volume decline
Introductory pressure is \[P\]
Increments in pressure \[=dP\]
Introductory volume is \[V\]
Diminishing in volume = \[-dV\] (- sign for diminishing volume)
Volumetric strain = change in volume/beginning volume
Volumetric strain = \[\dfrac{-dV}{V}\]
Mass modulus \[\left( k \right)=-V\dfrac{dP}{dV}\]
\[\left( k \right)=-\dfrac{dP}{dV}\times V\] ( condition - 1)
Unit of weight is \[N/{{m}^{2}}\]
Unit of volume is \[{{m}^{3}}\]
Put this unit in condition — - 1
We get unit of bulk modulus \[N/{{m}^{2}}\]
Presently compressibility is equal to mass modulus.
The compressibility of liquid is essentially a proportion of the adjustment in thickness that will be created in the liquid by a predetermined change in pressure. Gases are exceptionally compressible while most fluids have low compressibility.
The correct answer is B.
Note:
The deviation from the perfect gas conduction becomes especially large (or, proportionately, the compressibility factor wanders a long way from solidarity) and close to the basic point, or on account of high weight or low temperature.
In these cases, a summed-up compressibility figure or an elective condition of the state which is more qualified to the issue must be used to deliver the precise outcomes.
Complete answer:
Compressibility is the proportional of bulk modulus of flexibility (k). Bulk modulus is characterized as the proportion of compressive worry to the volumetric strain.
Consider a chamber loaded up with liquid and shut by cylinder when cylinder push ahead and pressure increment yet volume decline
Introductory pressure is \[P\]
Increments in pressure \[=dP\]
Introductory volume is \[V\]
Diminishing in volume = \[-dV\] (- sign for diminishing volume)
Volumetric strain = change in volume/beginning volume
Volumetric strain = \[\dfrac{-dV}{V}\]
Mass modulus \[\left( k \right)=-V\dfrac{dP}{dV}\]
\[\left( k \right)=-\dfrac{dP}{dV}\times V\] ( condition - 1)
Unit of weight is \[N/{{m}^{2}}\]
Unit of volume is \[{{m}^{3}}\]
Put this unit in condition — - 1
We get unit of bulk modulus \[N/{{m}^{2}}\]
Presently compressibility is equal to mass modulus.
The compressibility of liquid is essentially a proportion of the adjustment in thickness that will be created in the liquid by a predetermined change in pressure. Gases are exceptionally compressible while most fluids have low compressibility.
The correct answer is B.
Note:
The deviation from the perfect gas conduction becomes especially large (or, proportionately, the compressibility factor wanders a long way from solidarity) and close to the basic point, or on account of high weight or low temperature.
In these cases, a summed-up compressibility figure or an elective condition of the state which is more qualified to the issue must be used to deliver the precise outcomes.
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