
Which one of the following is most acidic in water?
A. $NiC{{l}_{2}}$
B. $BeC{{l}_{2}}$
C. $FeC{{l}_{3}}$
D. $AlC{{l}_{3}}$
Answer
305.1k+ views
Hint: Salt of a strong acid and weak base form acidic solution when it is dissolved in water. $AlC{{l}_{3}}$ on hydrolysis gives a weak base $[Al{{(OH)}_{3}}]$ and a strong acid $(HCl)$ among all. That’s why $AlC{{l}_{3}}$is more acidic in water than any other compound.
Complete Step by Step Answer:
$AlC{{l}_{3}}$( ammonium trichloride ) is hygroscopic. This means it absorbs water from the air. $AlC{{l}_{3}}$ is made from the mixture of a weak base $[Al{{(OH)}_{3}}]$ and a very strong acid $(HCl)$ which is hydrochloric acid. Chloride ion does not react with water as it is a weak base whereas the cations of the salt is a weak acid which reacts with water.
$AlC{{l}_{3}}+{{H}_{2}}O\to Al{{(OH)}_{3}}+3HCl$
All other compounds also give us strong acid $(HCl)$and their corresponding salts $Ni{{(OH)}_{2}},\,Be{{(OH)}_{2}}\,\,and\,\,Fe{{(OH)}_{2}}$, but among them $[Al{{(OH)}_{3}}]$is the weakest base.
We know weak bases are the substances which do not completely dissolve in water and the acidic behaviour is due to the presence of hydrogen ions. In $(HCl)$, all the hydrogen ions and the chloride ions dissociate to produce ${{H}^{+}}$ ions in the absence of water.
Thus the solution of $AlC{{l}_{3}}$ is more acidic.
Thus, Option (D) is correct.
Note: We can find the compound whether it is acidic, basic or neutral with the help of its ions which dissociates in water. A solution can be called acidic if there are more hydrogen ions than the hydroxide ions and the solution is basic if there are more hydroxide ions than the hydrogen ions.
Complete Step by Step Answer:
$AlC{{l}_{3}}$( ammonium trichloride ) is hygroscopic. This means it absorbs water from the air. $AlC{{l}_{3}}$ is made from the mixture of a weak base $[Al{{(OH)}_{3}}]$ and a very strong acid $(HCl)$ which is hydrochloric acid. Chloride ion does not react with water as it is a weak base whereas the cations of the salt is a weak acid which reacts with water.
$AlC{{l}_{3}}+{{H}_{2}}O\to Al{{(OH)}_{3}}+3HCl$
All other compounds also give us strong acid $(HCl)$and their corresponding salts $Ni{{(OH)}_{2}},\,Be{{(OH)}_{2}}\,\,and\,\,Fe{{(OH)}_{2}}$, but among them $[Al{{(OH)}_{3}}]$is the weakest base.
We know weak bases are the substances which do not completely dissolve in water and the acidic behaviour is due to the presence of hydrogen ions. In $(HCl)$, all the hydrogen ions and the chloride ions dissociate to produce ${{H}^{+}}$ ions in the absence of water.
Thus the solution of $AlC{{l}_{3}}$ is more acidic.
Thus, Option (D) is correct.
Note: We can find the compound whether it is acidic, basic or neutral with the help of its ions which dissociates in water. A solution can be called acidic if there are more hydrogen ions than the hydroxide ions and the solution is basic if there are more hydroxide ions than the hydrogen ions.
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