
Which of the following statements is correct for the reaction, at constant temperature and pressure?
$CO(g) + \dfrac{1}{2}{O_2}(g) \to C{O_2}(g)$
a.)$\Delta H = \Delta U$
b.)$\Delta H < \Delta U$
c.)$\Delta H > \Delta U$
d.)None of these
Answer
581.7k+ views
Hint: We have studied the relation between change in enthalpy and change in internal energy as-$\Delta H = \Delta U + \Delta {n_g}RT$
Where $\Delta H$ is the change in enthalpy, $\Delta U$ is the change in internal energy, $\Delta {n_g}$ is the change in gaseous moles.
Complete step by step solution:
We will first study the reaction and then see which option is our answer.
So, the reaction is:-
$CO(g) + \dfrac{1}{2}{O_2}(g) \to C{O_2}(g)$
To calculate whether the Change in enthalpy is equal to, less than or greater than the change in internal energy, we will see their relationship which is-
$\Delta H = \Delta U + \Delta {n_g}RT$
Let this be the 1st equation.
It can be defined that the Enthalpy of a system is the sum of internal energy and the work required to achieve its pressure and volume.
Further, the equation PV=nRT
We have change in internal energy is-
$\Delta U = nR\Delta T$
From the question, it is clear that Temperature is constant i.e. $\Delta T$=0
$\begin{gathered}
\Delta U = nR\left( 0 \right) \\
\Delta U = 0 \\
\end{gathered} $
Now, from the reaction we can find out value of $\Delta {n_g}$as-
$\Delta {n_g} = 1 - 1 - \dfrac{1}{2} = \left( { - \dfrac{1}{2}} \right)$
Thus, $\Delta H = 0 + \left( { - \dfrac{1}{2}} \right)RT$
$\Delta H = \left( { - \dfrac{1}{2}} \right)RT$
Thus, $\Delta H < \Delta U$
So, the correct answer is “Option B”.
Additional Information:
Enthalpy is an extensive property. It is directly proportional to the size of the system.
The total enthalpy of a system can not be measured directly; instead, we measure the change in enthalpy. For exothermic reactions at constant pressure, the change in enthalpy of a system is equal to the sum of energy released in the reaction, energy retained in the system and energy lost in expansion.
Note: When the temperature is constant; then change in temperature will be zero. The unit for enthalpy is Joule.
Where $\Delta H$ is the change in enthalpy, $\Delta U$ is the change in internal energy, $\Delta {n_g}$ is the change in gaseous moles.
Complete step by step solution:
We will first study the reaction and then see which option is our answer.
So, the reaction is:-
$CO(g) + \dfrac{1}{2}{O_2}(g) \to C{O_2}(g)$
To calculate whether the Change in enthalpy is equal to, less than or greater than the change in internal energy, we will see their relationship which is-
$\Delta H = \Delta U + \Delta {n_g}RT$
Let this be the 1st equation.
It can be defined that the Enthalpy of a system is the sum of internal energy and the work required to achieve its pressure and volume.
Further, the equation PV=nRT
We have change in internal energy is-
$\Delta U = nR\Delta T$
From the question, it is clear that Temperature is constant i.e. $\Delta T$=0
$\begin{gathered}
\Delta U = nR\left( 0 \right) \\
\Delta U = 0 \\
\end{gathered} $
Now, from the reaction we can find out value of $\Delta {n_g}$as-
$\Delta {n_g} = 1 - 1 - \dfrac{1}{2} = \left( { - \dfrac{1}{2}} \right)$
Thus, $\Delta H = 0 + \left( { - \dfrac{1}{2}} \right)RT$
$\Delta H = \left( { - \dfrac{1}{2}} \right)RT$
Thus, $\Delta H < \Delta U$
So, the correct answer is “Option B”.
Additional Information:
Enthalpy is an extensive property. It is directly proportional to the size of the system.
The total enthalpy of a system can not be measured directly; instead, we measure the change in enthalpy. For exothermic reactions at constant pressure, the change in enthalpy of a system is equal to the sum of energy released in the reaction, energy retained in the system and energy lost in expansion.
Note: When the temperature is constant; then change in temperature will be zero. The unit for enthalpy is Joule.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

