
Which of the following statements are correct about the reactivities of (I) n-propyl chloride and (II) allyl chloride?
(A) Rate if ${S_N}1$ reaction of (I) $ > $(II)
(B) Rate if ${S_N}1$ reaction of (II) $ > $(I)
(C) Rate if ${S_N}2$ reaction of (I) $ > $(II)
(D) Rate if ${S_N}2$ reaction of (II) $ > $(I)
Answer
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Hint: Tertiary alkyl halides are most reactive for ${S_N}1$ reactions and similarly, primary halides for ${S_N}2$ reactions.
The rate of these reactions depends upon the types of compounds.
Also, which mechanism will be more favored is dependent on it.
Complete step by step answer:
The IUPAC name of n-propyl chloride is given as
1-Chloropropane
And that of allyl chloride is given as
3-Chloroprop-1-ene
The structure of n-propyl chloride is
$C{H_3} - C{H_2} - C{H_2} - Cl$
The structure of allyl chloride is
$C{H_2} = CH - C{H_2} - Cl$
Here, both the chlorine atoms are attached to primary carbon but in allyl chloride, there is a double bond present.
The reactivity of ${S_N}1$ reaction is given as
Tertiary alkyl halide $ > $ secondary alkyl halide $ > $ primary alkyl halide
And the reactivity of ${S_N}2$ reaction is given as
Primary alkyl halide $ > $ secondary alkyl halide $ > $ Tertiary alkyl halide
The allyl chloride molecule is stabilized by resonance.
Therefore, it’s more reactive. It is reactive in both ${S_N}1$ and ${S_N}2$ mechanisms but more in ${S_N}1$ mechanism.
Both the molecules are similar except for the double bond in allyl chloride.
So, they both will undergo ${S_N}2$ mechanisms but as allyl chloride is more reactive than n-propyl chloride, the rate of nucleophilic substitution of allyl chloride will be more in both ${S_N}1$ and ${S_N}2$ mechanisms.
Therefore, the correct options are
Option (B) Rate if ${S_N}1$ reaction of (II) $ > $ (I) and
Option (D) Rate if ${S_N}2$ reaction of (II) $ > $ (I)
So, the correct answer is Option B,D.
Note: ${S_N}1$ and ${S_N}2$ reactions are nucleophilic substitution reactions .
For ${S_N}1$, there is one rate-determining step and is unimolecular.
And for ${S_N}2$ reaction there are two rate-determining steps and is a bimolecular reaction.
There is a difference in energy levels of the two reactions as well.
The rate of these reactions depends upon the types of compounds.
Also, which mechanism will be more favored is dependent on it.
Complete step by step answer:
The IUPAC name of n-propyl chloride is given as
1-Chloropropane
And that of allyl chloride is given as
3-Chloroprop-1-ene
The structure of n-propyl chloride is
$C{H_3} - C{H_2} - C{H_2} - Cl$
The structure of allyl chloride is
$C{H_2} = CH - C{H_2} - Cl$
Here, both the chlorine atoms are attached to primary carbon but in allyl chloride, there is a double bond present.
The reactivity of ${S_N}1$ reaction is given as
Tertiary alkyl halide $ > $ secondary alkyl halide $ > $ primary alkyl halide
And the reactivity of ${S_N}2$ reaction is given as
Primary alkyl halide $ > $ secondary alkyl halide $ > $ Tertiary alkyl halide
The allyl chloride molecule is stabilized by resonance.
Therefore, it’s more reactive. It is reactive in both ${S_N}1$ and ${S_N}2$ mechanisms but more in ${S_N}1$ mechanism.
Both the molecules are similar except for the double bond in allyl chloride.
So, they both will undergo ${S_N}2$ mechanisms but as allyl chloride is more reactive than n-propyl chloride, the rate of nucleophilic substitution of allyl chloride will be more in both ${S_N}1$ and ${S_N}2$ mechanisms.
Therefore, the correct options are
Option (B) Rate if ${S_N}1$ reaction of (II) $ > $ (I) and
Option (D) Rate if ${S_N}2$ reaction of (II) $ > $ (I)
So, the correct answer is Option B,D.
Note: ${S_N}1$ and ${S_N}2$ reactions are nucleophilic substitution reactions .
For ${S_N}1$, there is one rate-determining step and is unimolecular.
And for ${S_N}2$ reaction there are two rate-determining steps and is a bimolecular reaction.
There is a difference in energy levels of the two reactions as well.
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