Answer
Verified
393.9k+ views
Hint: The term ‘caproic acid’ is the common name given to hexanoic acid. It is a member of the carboxylic acid group. As the name suggests, it has six carbon atoms. Its molecular formula is ${C_5}{H_{11}}COOH$ . It can be prepared by any method that can be applied for the production of carboxylic acids.
Complete step by step answer:
A.When we react n-bromopentane ($n - {C_5}{H_{11}}Br$) with magnesium metal in the presence of dry ether and carbon dioxide, then we get caproic acid (i.e., hexanoic acid). The reaction can be given as follows:
\[n - {C_5}{H_{11}}Br\xrightarrow[{(ii)C{O_2}}]{{(i)Mg/Ether}}{C_5}{H_{11}}COOH\]
B.When we react $n - {C_5}{H_{11}}Li$ with carbon dioxide followed by hydrolysis, we obtain the following product:
$n - {C_5}{H_{11}}Li\xrightarrow[{(ii){H_3}{O^ + }}]{{(i)C{O_2}}}{C_5}{H_{11}} - CO - {C_5}{H_{11}}$
C.When we react n-bromobutane ($n - {C_4}{H_9}Br$) with magnesium metal in the presence of dry ether and then with carbon dioxide followed by hydrolysis, then we get pentanoic acid. The chemical reaction can be given as follows:
$n - {C_4}{H_9}Br\xrightarrow[{(ii)C{O_2}(iii){H_3}{O^ + }}]{{(i)Mg/Ether}}{C_4}{H_9}COOH$
D.When we heat pentyl magnesium bromide ($n - {C_5}{H_{11}}MgBr$) with ${(CN)_2}$followed by hydrolysis, then we get caproic acid as follows:
$n - {C_5}{H_{11}}MgBr + {(CN)_2}\xrightarrow{{(i)\Delta }}{C_5}{H_{11}}CN + MgBrCN\xrightarrow{{(ii){H_3}{O^ + }}}{C_5}{H_{11}}COOH$
Thus option-A and D are correct.
Note:
The formation of caproic acid takes place as follows:
-When an alkyl halide reacts with magnesium in the presence of dry ether, we obtain a Grignard reagent.
-When a Grignard reagent reacts with carbon dioxide followed by the addition of a proton, then a carboxylic acid is formed with one carbon more than the Grignard reagent.
-Hence we obtain hexanoic acid from n-bromopentane.
-Also, when we react to a Grignard reagent with cyanogen ${(CN)_2}$, then we get hexanenitrile.
-Hexanenitrile gives hexanoic acid upon further hydrolysis.
Complete step by step answer:
A.When we react n-bromopentane ($n - {C_5}{H_{11}}Br$) with magnesium metal in the presence of dry ether and carbon dioxide, then we get caproic acid (i.e., hexanoic acid). The reaction can be given as follows:
\[n - {C_5}{H_{11}}Br\xrightarrow[{(ii)C{O_2}}]{{(i)Mg/Ether}}{C_5}{H_{11}}COOH\]
B.When we react $n - {C_5}{H_{11}}Li$ with carbon dioxide followed by hydrolysis, we obtain the following product:
$n - {C_5}{H_{11}}Li\xrightarrow[{(ii){H_3}{O^ + }}]{{(i)C{O_2}}}{C_5}{H_{11}} - CO - {C_5}{H_{11}}$
C.When we react n-bromobutane ($n - {C_4}{H_9}Br$) with magnesium metal in the presence of dry ether and then with carbon dioxide followed by hydrolysis, then we get pentanoic acid. The chemical reaction can be given as follows:
$n - {C_4}{H_9}Br\xrightarrow[{(ii)C{O_2}(iii){H_3}{O^ + }}]{{(i)Mg/Ether}}{C_4}{H_9}COOH$
D.When we heat pentyl magnesium bromide ($n - {C_5}{H_{11}}MgBr$) with ${(CN)_2}$followed by hydrolysis, then we get caproic acid as follows:
$n - {C_5}{H_{11}}MgBr + {(CN)_2}\xrightarrow{{(i)\Delta }}{C_5}{H_{11}}CN + MgBrCN\xrightarrow{{(ii){H_3}{O^ + }}}{C_5}{H_{11}}COOH$
Thus option-A and D are correct.
Note:
The formation of caproic acid takes place as follows:
-When an alkyl halide reacts with magnesium in the presence of dry ether, we obtain a Grignard reagent.
-When a Grignard reagent reacts with carbon dioxide followed by the addition of a proton, then a carboxylic acid is formed with one carbon more than the Grignard reagent.
-Hence we obtain hexanoic acid from n-bromopentane.
-Also, when we react to a Grignard reagent with cyanogen ${(CN)_2}$, then we get hexanenitrile.
-Hexanenitrile gives hexanoic acid upon further hydrolysis.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The cell wall of prokaryotes are made up of a Cellulose class 9 biology CBSE
What organs are located on the left side of your body class 11 biology CBSE
Select the word that is correctly spelled a Twelveth class 10 english CBSE
a Tabulate the differences in the characteristics of class 12 chemistry CBSE