Question

Which of the following is the ionic carbide?
A. $F{e_3}C$
B. $SiC$
C. $Ca{C_2}$
D. $C{u_2}C$

Answer 1

Hint: To answer this question, you should recall the concept of ionic bond. Chemical Bonding refers to the formation of a chemical bond between two or more atoms, molecules, or ions to give rise to a chemical compound. Ionic bonds are formed by the complete transfer of electrons between the atoms to complete their octets.

Complete Step by step solution:
Ionic bonding is a type of chemical bonding which involves a transfer of electrons from one atom or molecule to another. Here, an atom loses an electron which is in turn gained by another atom. When such an electron transfer takes place, one of the atoms develops a negative charge and is now called the anion. The other atom develops a positive charge and is called the cation. Ionic bonds are mostly formed by atoms with a high difference in electronegativity.
\[Ca{C_2},A{l_4}C{l_3}{\text{ and }}B{e_2}C\] are ionic carbides but \[SiC\] are covalent.

Hence, options A, B and D are correct.

Note: In ideal cases, it can be said that any bond is hundred percent ionic or covalent. But in reality, any bond shows partial ionic and covalent character. The components of any molecular: the cations polarize the anions and try to pull the electronic charge towards themselves and this increases the electric charge between the two ions. This is the case with a covalent bond, that is an electron charge density is built up around the nuclei. Fajan’s rule is based on the fact that:
Smaller the size of cation, larger the size of the anion will result in a more covalent character of the ionic bond.
More the charge density of cation, greater is the covalent character of the ionic bond.
Electronic configuration: For cations with same charge and size, the one, with \[\left( {n - 1} \right){d^{n}}n{s^o}\] which is found in transition elements have greater covalent character than the cation with \[n{s^{2}}n{p^6}\] electronic configuration, generally present s- block elements.