Which of the following is divisible by 11?
A. \[3,116,365\]
B. \[901,351\]
C. \[8,790,322\]
D.NONE OF THESE
Answer
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Hint: Here, we are given some numbers and we are required to see which number is divisible by \[11\]. We will use the divisibility test of \[11\] which is after subtraction of the sum of the digit at an even place from the sum of the digit at odd places if we get 0, \[11\] OR MULTIPLE OF \[11\] then the number is divisible by 11\[11\]and will check which number is divisible by \[11\].
Now, check each number by the rule step by step.
FORMULA USED: Sum of the digit at odd places\[ - \]sum of the digit at even places \[ = \] 0 or divisible by \[11\]
Complete answer:
We know that,
Divisibility test of \[11\] states that the sum of the digit at even place is subtracted at odd places digit the result will be either 0 or divisible by \[11\]
Now we will test it through all options
Taking option, A
A. \[3,116,365\]
Here odd place digit is \[ = \]\[3,1,3,5,1,6,6\]
Even place digit is \[ = \] \[1,6,6\]
As we know that,
Sum of the digit at odd places \[ - \]sum of the digit at even places \[ = \]0 or divisible by \[11\]
\[\left( {3 + 1 + 3 + 5} \right) - \left( {1 + 6 + 6} \right)\]
\[ = \]\[12 - 13\]
\[ = \]\[ - 1\]
Here, the result is \[ - \]1 therefore
It is not divisible \[11\].
B. \[901,351\]
Here odd place digit is \[ = \]\[9,1,5\]
Even place digit is \[ = \]\[0,3,1\]
As we know that,
Sum of the digit at odd places \[ - \]sum of the digit at even places \[ = \]0 or divisible by 11
\[\left( {9 + 1 + 5} \right) - \left( {0 + 3 + 1} \right)\]
\[ = \] \[11\]
Here, the result is \[11\].
So, it is divisible by \[11\].
C. \[8,790,322\]
Here odd place digit is \[ = \]\[8,9,3,2\]
Even place digit is \[ = \]\[7,0,2\]
As we know that,
Sum of the digit at odd places \[ - \]sum of the digit at even places\[ = \]0 or divisible by \[11\]
\[\left( {8 + 9 + 3 + 2} \right) - \left( {7 + 0 + 2} \right)\]
\[ = \] \[13\]
Here, the result is \[13\].
therefore, it is not divisible by \[11\]
Therefore, the correct option is B
Note: Divisibility tests are shortcut methods to identify that a number is divisible by another number without dividing it.
Whenever we face such a type of question the key concept is to go through the divisibility rule.
So, always keep in mind the divisibility rule of the number to find out the result quickly.
Now, check each number by the rule step by step.
FORMULA USED: Sum of the digit at odd places\[ - \]sum of the digit at even places \[ = \] 0 or divisible by \[11\]
Complete answer:
We know that,
Divisibility test of \[11\] states that the sum of the digit at even place is subtracted at odd places digit the result will be either 0 or divisible by \[11\]
Now we will test it through all options
Taking option, A
A. \[3,116,365\]
Here odd place digit is \[ = \]\[3,1,3,5,1,6,6\]
Even place digit is \[ = \] \[1,6,6\]
As we know that,
Sum of the digit at odd places \[ - \]sum of the digit at even places \[ = \]0 or divisible by \[11\]
\[\left( {3 + 1 + 3 + 5} \right) - \left( {1 + 6 + 6} \right)\]
\[ = \]\[12 - 13\]
\[ = \]\[ - 1\]
Here, the result is \[ - \]1 therefore
It is not divisible \[11\].
B. \[901,351\]
Here odd place digit is \[ = \]\[9,1,5\]
Even place digit is \[ = \]\[0,3,1\]
As we know that,
Sum of the digit at odd places \[ - \]sum of the digit at even places \[ = \]0 or divisible by 11
\[\left( {9 + 1 + 5} \right) - \left( {0 + 3 + 1} \right)\]
\[ = \] \[11\]
Here, the result is \[11\].
So, it is divisible by \[11\].
C. \[8,790,322\]
Here odd place digit is \[ = \]\[8,9,3,2\]
Even place digit is \[ = \]\[7,0,2\]
As we know that,
Sum of the digit at odd places \[ - \]sum of the digit at even places\[ = \]0 or divisible by \[11\]
\[\left( {8 + 9 + 3 + 2} \right) - \left( {7 + 0 + 2} \right)\]
\[ = \] \[13\]
Here, the result is \[13\].
therefore, it is not divisible by \[11\]
Therefore, the correct option is B
Note: Divisibility tests are shortcut methods to identify that a number is divisible by another number without dividing it.
Whenever we face such a type of question the key concept is to go through the divisibility rule.
So, always keep in mind the divisibility rule of the number to find out the result quickly.
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