
Which of the following is correct?
(a) \[\left( p\vee q \right)\equiv \left( p\wedge q \right)\]
(b) \[\left( p\to q \right)\equiv \left( q\to p \right)\]
(c) \[\left( p\to q \right)\equiv \left( p\wedge q \right)\]
(d) None of these
Answer
567.6k+ views
Hint: Draw a truth table for each expression provided in the options using the properties of Boolean Algebra. Check if the L.H.S. of the expression for particular values of p and q is equal to the R.H.S. of the same expression for the same particular values of p and q or not. If they are equal then the expression will be equivalent otherwise not.
Complete step by step answer:
Here, we have been provided with some Boolean expressions in the given options and we have to determine the correct option in which the two sides of the expression are equivalent. So, let us draw truth tables for each option and check them – by – one.
(a) \[\left( p\vee q \right)\equiv \left( p\wedge q \right)\]
Drawing the truth table for the above expression, we get,
Clearly, we can see that the truth values for the expressions \[\left( p\vee q \right)\] and \[\left( p\wedge q \right)\] are not the same. So, we have L.H.S \[\ne \] R.H.S. therefore, the two expressions are not equivalent.
(b) \[\left( p\to q \right)\equiv \left( q\to p \right)\]
Drawing the truth table for the above expression, we get,
Clearly, we can see that the truth values of the expressions \[\left( p\to q \right)\] and \[\left( q\to p \right)\] are not the same for particular values of p and q. so, we have L.H.S \[\ne \] R.H.S. therefore, the two expressions are not equivalent.
(c) \[\left( p\to q \right)\equiv \left( p\wedge q \right)\]
Drawing the truth table for the above expression, we get,
Clearly, we can see that the truth tables for the expressions \[\left( p\to q \right)\] and \[\left( p\wedge q \right)\] are not the same. So, we have L.H.S \[\ne \] R.H.S. Therefore, the two expressions are not equivalent.
On observing all the truth tables for the expressions provided in each option we can conclude that none of the three options have equivalent expressions on both sides.
Hence, option (d) is the correct answer.
Note:
One may note that the truth table for the expression in option (b) can confuse us. Here, we have three T’s for both the expressions \[p\to q\] and \[q\to p\] and only one F. But that does not mean both the expressions are equivalent because the truth values are not the same for corresponding values of p and q. You must remember the truth tables for basic expressions like: - \[p\vee q\], \[p\wedge q\], \[p\to q\] and \[p\leftrightarrow q\] as they are used everywhere.
Complete step by step answer:
Here, we have been provided with some Boolean expressions in the given options and we have to determine the correct option in which the two sides of the expression are equivalent. So, let us draw truth tables for each option and check them – by – one.
(a) \[\left( p\vee q \right)\equiv \left( p\wedge q \right)\]
Drawing the truth table for the above expression, we get,
| p | q | \[p\vee q\] | \[p\wedge q\] |
| T | T | T | T |
| T | F | T | F |
| F | T | T | F |
| F | F | F | F |
Clearly, we can see that the truth values for the expressions \[\left( p\vee q \right)\] and \[\left( p\wedge q \right)\] are not the same. So, we have L.H.S \[\ne \] R.H.S. therefore, the two expressions are not equivalent.
(b) \[\left( p\to q \right)\equiv \left( q\to p \right)\]
Drawing the truth table for the above expression, we get,
| p | q | \[p\to q\] | \[q\to p\] |
| T | T | T | T |
| T | F | F | T |
| F | T | T | F |
| F | F | T | T |
Clearly, we can see that the truth values of the expressions \[\left( p\to q \right)\] and \[\left( q\to p \right)\] are not the same for particular values of p and q. so, we have L.H.S \[\ne \] R.H.S. therefore, the two expressions are not equivalent.
(c) \[\left( p\to q \right)\equiv \left( p\wedge q \right)\]
Drawing the truth table for the above expression, we get,
| p | q | \[p\wedge q\] | \[p\to q\] |
| T | T | T | T |
| T | F | F | F |
| F | T | F | T |
| F | F | F | T |
Clearly, we can see that the truth tables for the expressions \[\left( p\to q \right)\] and \[\left( p\wedge q \right)\] are not the same. So, we have L.H.S \[\ne \] R.H.S. Therefore, the two expressions are not equivalent.
On observing all the truth tables for the expressions provided in each option we can conclude that none of the three options have equivalent expressions on both sides.
Hence, option (d) is the correct answer.
Note:
One may note that the truth table for the expression in option (b) can confuse us. Here, we have three T’s for both the expressions \[p\to q\] and \[q\to p\] and only one F. But that does not mean both the expressions are equivalent because the truth values are not the same for corresponding values of p and q. You must remember the truth tables for basic expressions like: - \[p\vee q\], \[p\wedge q\], \[p\to q\] and \[p\leftrightarrow q\] as they are used everywhere.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

