
Which of the following is an incorrect statement?
A. $Pb{{F}_{4}}$ is covalent in nature
B. $SiC{{l}_{4}}$ is easily hydrolyzed
C. $Ge{{X}_{4}}$ (X = F, Cl, Br, I) is more stable than $Ge{{X}_{2}}$
D. $Sn{{F}_{4}}$ is ionic in nature
Answer
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Hint: The elements named fluorine, chlorine, bromine, iodine, and astatine are kept in the category of halogen atoms and the word halogen is basically a Greek word having the meaning of salt producer. Halogens are very reactive in nature.
Complete step by step answer:
The compounds given in the question are basically halides and halides can be defined as binary compounds in which one part is an element and another part is of the halogen atom. Most of the salts are halide in nature.
A. $Pb{{F}_{4}}$ is covalent in nature: This statement is not true as we know that Pb is a very large atom and F is very small in size so according to Fajan’ rule $Pb{{F}_{4}}$ is not covalent in nature.
B. $SiC{{l}_{4}}$ is easily hydrolyzed: This compound is not a very stable compound and we know that those compounds which are unstable in nature can be easily dissociated or hydrolyzed so this statement is true.
C. $Ge{{X}_{4}}$(X = F, Cl, Br, I) is more stable than $Ge{{X}_{2}}$: This statement is also true because in the case of $Ge{{X}_{4}}$ all the orbitals are fully filled.
D. $Sn{{F}_{4}}$ is ionic in nature: This statement is true as we know that Sn is a very large atom and F is very small in size so according to Fajan’s rule $Sn{{F}_{4}}$ is ionic in nature.
So, the correct answer is “Option A”.
Note: Halogen atom which has a negative charge on them considered in the category of hydrides. Fajan’s rule is the rule which specifies whether the given compound is ionic or covalent in nature. It is based on three rules.
Complete step by step answer:
The compounds given in the question are basically halides and halides can be defined as binary compounds in which one part is an element and another part is of the halogen atom. Most of the salts are halide in nature.
A. $Pb{{F}_{4}}$ is covalent in nature: This statement is not true as we know that Pb is a very large atom and F is very small in size so according to Fajan’ rule $Pb{{F}_{4}}$ is not covalent in nature.
B. $SiC{{l}_{4}}$ is easily hydrolyzed: This compound is not a very stable compound and we know that those compounds which are unstable in nature can be easily dissociated or hydrolyzed so this statement is true.
C. $Ge{{X}_{4}}$(X = F, Cl, Br, I) is more stable than $Ge{{X}_{2}}$: This statement is also true because in the case of $Ge{{X}_{4}}$ all the orbitals are fully filled.
D. $Sn{{F}_{4}}$ is ionic in nature: This statement is true as we know that Sn is a very large atom and F is very small in size so according to Fajan’s rule $Sn{{F}_{4}}$ is ionic in nature.
So, the correct answer is “Option A”.
Note: Halogen atom which has a negative charge on them considered in the category of hydrides. Fajan’s rule is the rule which specifies whether the given compound is ionic or covalent in nature. It is based on three rules.
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