
Which of the following has the highest weight?
A.) \[1{m^3}\] of water
B.) A normal adult man
C.) 10 L of Hg
D.) All have the same weight
Answer
604.2k+ views
Hint: If the density of a substance is known, its weight can be estimated by assuming some volume. It can also be found if the volume of the substance is given.
Complete step by step answer:
The density of a substance is defined as its mass per unit volume. Mathematically, it is represented as:
\[\rho = \dfrac{m}{V}\]
Density is loosely defined as its weight per unit volume, although this is scientifically inaccurate, this quantity is more specifically called specific weight. For a pure substance the density has the same numerical value as its mass concentration.
In the given question, we will need to investigate each option individually:
\[1{m^3}\] of water
The density of water is equal to 1000 \[\dfrac{{kg}}{{{m^3}}}\]
The given value of volume is equal to \[1{m^3}\].
Hence,
Mass of water = \[\rho \times V\]
= 1000 $\times$ 1
= 1000 kg
A normal adult man
An average adult man weighs around 65 kg. This is definitely lesser than what obtained in part (A).
10 L of Hg
The density of mercury is equal to 13.6 \[\dfrac{g}{{mL}}\]
The given volume of mercury is equal to 10L
Thus,
Mass of mercury = \[\rho \times V\]
= 13.6 10 kg
= 136 kg
All have the same weight
It is clearly seen that all the above options do not have the same weight.
Hence, the correct option is (A).
Note: Remember that to find the respective masses, we need to know the densities of the substances. Else, it would be very difficult to get the correct answer.
Complete step by step answer:
The density of a substance is defined as its mass per unit volume. Mathematically, it is represented as:
\[\rho = \dfrac{m}{V}\]
Density is loosely defined as its weight per unit volume, although this is scientifically inaccurate, this quantity is more specifically called specific weight. For a pure substance the density has the same numerical value as its mass concentration.
In the given question, we will need to investigate each option individually:
\[1{m^3}\] of water
The density of water is equal to 1000 \[\dfrac{{kg}}{{{m^3}}}\]
The given value of volume is equal to \[1{m^3}\].
Hence,
Mass of water = \[\rho \times V\]
= 1000 $\times$ 1
= 1000 kg
A normal adult man
An average adult man weighs around 65 kg. This is definitely lesser than what obtained in part (A).
10 L of Hg
The density of mercury is equal to 13.6 \[\dfrac{g}{{mL}}\]
The given volume of mercury is equal to 10L
Thus,
Mass of mercury = \[\rho \times V\]
= 13.6 10 kg
= 136 kg
All have the same weight
It is clearly seen that all the above options do not have the same weight.
Hence, the correct option is (A).
Note: Remember that to find the respective masses, we need to know the densities of the substances. Else, it would be very difficult to get the correct answer.
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