
Which of the following has high resonance energy among the following pairs?
A. \[C{H_3}COOH\] and \[C{H_3}COONa\]
B. \[C{H_2} = C{H^ - }\] and \[C{H_2} = CH - OH\]
C.
D.
E.
and \[C{H_2} = CH - CH = CH - CH = C{H_2}\]
Answer
465.3k+ views
Hint: In order to answer this question, we should know about the concept of resonance energy. The resonance energy of a compound depends on its stability and aromaticity. For this question, we have to compare the aromaticity of the compounds given in pairs.
Complete answer:
Let’s completely understand the solution to this question.
First, let us know about the phenomenon named resonance. Resonance is the withdrawal or releasing effect of electrons attributed to a specific substituents through the delocalization of pi- electrons in organic compounds. This effect is resonance or mesomeric effect.
Here, in this question, we need to compare the resonance energy. The resonance energy is dependent on the stability and aromaticity of the compounds. Resonance energy is directly proportional stability of the compound as well as aromaticity.
Resonance energy is the difference in the energy between the most stable contributing structure for a compound and its resonance hybrid is resonance energy.
Let’s have a look at each pair one by one.
A. \[C{H_3}COOH\] and \[C{H_3}COONa\]
Here, \[C{H_3}COONa\] has \[N{a^ + }\]cation which leaves this group and becomes \[C{H_3}CO{O^ - }\] . This negative charge get delocalized with a pi bond or we can say pi electrons of the \[C = O\] group.
Let’s see the resonance structure of \[C{H_3}CO{O^ - }\]
Therefore, \[C{H_3}COONa\] has high resonance energy as it shows more resonance.
Similarly, we see compare the resonance energy of other given pairs by observing the delocalization of the pi- electrons
B. \[C{H_2} = C{H^ - }\] and \[C{H_2} = CH - OH\]
Here, oxygen is more electronegative than carbon. So, oxygen pulls the electrons more easily than carbon. Therefore, \[C{H_2} = CH - OH\] has more resonance energy than \[C{H_2} = C{H^ - }\].
C.
is a more stable resonance. Hence, more resonance energy.
D.
In this case, the two benzene rings which are connected with a common bond show complete resonance in the structure.
Therefore,
has more resonance energy.
E.
and \[C{H_2} = CH - CH = CH - CH = C{H_2}\]
In this pair, the benzene ring is an aromatic compound so it will show more resonance. Hence, it has more resonance energy.
Note:
Resonance energy is also called resonance stabilization energy. This is so because it depends upon the stability and aromaticity of the compounds. Also, it depends upon the electronegativity of the heteroatom like oxygen, nitrogen etc. attached to the organic compound.
Complete answer:
Let’s completely understand the solution to this question.
First, let us know about the phenomenon named resonance. Resonance is the withdrawal or releasing effect of electrons attributed to a specific substituents through the delocalization of pi- electrons in organic compounds. This effect is resonance or mesomeric effect.
Here, in this question, we need to compare the resonance energy. The resonance energy is dependent on the stability and aromaticity of the compounds. Resonance energy is directly proportional stability of the compound as well as aromaticity.
Resonance energy is the difference in the energy between the most stable contributing structure for a compound and its resonance hybrid is resonance energy.
Let’s have a look at each pair one by one.
A. \[C{H_3}COOH\] and \[C{H_3}COONa\]
Here, \[C{H_3}COONa\] has \[N{a^ + }\]cation which leaves this group and becomes \[C{H_3}CO{O^ - }\] . This negative charge get delocalized with a pi bond or we can say pi electrons of the \[C = O\] group.
Let’s see the resonance structure of \[C{H_3}CO{O^ - }\]
Therefore, \[C{H_3}COONa\] has high resonance energy as it shows more resonance.
Similarly, we see compare the resonance energy of other given pairs by observing the delocalization of the pi- electrons
B. \[C{H_2} = C{H^ - }\] and \[C{H_2} = CH - OH\]
Here, oxygen is more electronegative than carbon. So, oxygen pulls the electrons more easily than carbon. Therefore, \[C{H_2} = CH - OH\] has more resonance energy than \[C{H_2} = C{H^ - }\].
C.
D.
In this case, the two benzene rings which are connected with a common bond show complete resonance in the structure.
Therefore,
E.
In this pair, the benzene ring is an aromatic compound so it will show more resonance. Hence, it has more resonance energy.
Note:
Resonance energy is also called resonance stabilization energy. This is so because it depends upon the stability and aromaticity of the compounds. Also, it depends upon the electronegativity of the heteroatom like oxygen, nitrogen etc. attached to the organic compound.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

