
Which of the following can be regarded as a gas so that gas laws could be applicable, within the commonly encountered temperature limits?
(a) ${{O}_{2}},\text{ }{{N}_{2}},\text{ }C{{O}_{2}},\text{ }steam$
(b) ${{O}_{2}},\text{ }{{N}_{2}},\text{ water vapor}$
(c) $S{{O}_{2}},\text{ }N{{H}_{3}},\text{ }C{{O}_{2}},\text{ moisture}$
(d) ${{O}_{2}},\text{ }{{N}_{2}},\text{ }{{\text{H}}_{2}},\text{ air}$
Answer
585.3k+ views
Hint: Gas laws can be applied to the gases that have very little atomic interactions, the gases which have very low volume, and the gases must be non-polarized.
Complete step by step answer:
The gas laws are applied to those gases within commonly encountered temperature limits, in which the atomic interactions are very little. The volume of the gas must be low as compared to the volume of the container. The gases must be non-polarized.
So, in ${{O}_{2}},\text{ }{{N}_{2}},\text{ }C{{O}_{2}},\text{ }steam$, the carbon dioxide and steam are heavy gases and their force of attraction is also high. So, the gas law cannot be applied to all the gases.
In ${{O}_{2}},\text{ }{{N}_{2}},\text{ water vapor}$, water vapor is a heavy gas whose volume is not negligible as compared to the volume of the container. So, the gas law cannot be applied to all the gases.
In $S{{O}_{2}},\text{ }N{{H}_{3}},\text{ }C{{O}_{2}},\text{ moisture}$, all the gases are heavy gases and their volume is also large. $N{{H}_{3}}$ is a polar molecule. And the atomic interactions between the molecules of these gases are also very strong. So, the gas law cannot be applied to all the gases.
In ${{O}_{2}},\text{ }{{N}_{2}},\text{ }{{\text{H}}_{2}},\text{ air}$, all the gases are lighter due to their volume is very low as compared to the volume of the container. All the gases are non-polarized and their atomic interactions are also not strong. So, the gas law can be applied to all the gases.
So, the correct answer is an option (d) ${{O}_{2}},\text{ }{{N}_{2}},\text{ }{{\text{H}}_{2}},\text{ air}$.
Note: The gas laws are Boyle’s law: “The volume of the gas is inversely proportional to the pressure at constant temperature”. Charle’s law: "The volume of the gas is directly proportional to the temperature at constant pressure". Avogadro's law: "At the same temperature and pressure the gases with equal volumes will have an equal number of gases".
Complete step by step answer:
The gas laws are applied to those gases within commonly encountered temperature limits, in which the atomic interactions are very little. The volume of the gas must be low as compared to the volume of the container. The gases must be non-polarized.
So, in ${{O}_{2}},\text{ }{{N}_{2}},\text{ }C{{O}_{2}},\text{ }steam$, the carbon dioxide and steam are heavy gases and their force of attraction is also high. So, the gas law cannot be applied to all the gases.
In ${{O}_{2}},\text{ }{{N}_{2}},\text{ water vapor}$, water vapor is a heavy gas whose volume is not negligible as compared to the volume of the container. So, the gas law cannot be applied to all the gases.
In $S{{O}_{2}},\text{ }N{{H}_{3}},\text{ }C{{O}_{2}},\text{ moisture}$, all the gases are heavy gases and their volume is also large. $N{{H}_{3}}$ is a polar molecule. And the atomic interactions between the molecules of these gases are also very strong. So, the gas law cannot be applied to all the gases.
In ${{O}_{2}},\text{ }{{N}_{2}},\text{ }{{\text{H}}_{2}},\text{ air}$, all the gases are lighter due to their volume is very low as compared to the volume of the container. All the gases are non-polarized and their atomic interactions are also not strong. So, the gas law can be applied to all the gases.
So, the correct answer is an option (d) ${{O}_{2}},\text{ }{{N}_{2}},\text{ }{{\text{H}}_{2}},\text{ air}$.
Note: The gas laws are Boyle’s law: “The volume of the gas is inversely proportional to the pressure at constant temperature”. Charle’s law: "The volume of the gas is directly proportional to the temperature at constant pressure". Avogadro's law: "At the same temperature and pressure the gases with equal volumes will have an equal number of gases".
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

