
Which molecule/ion among the following cannot act as a ligand in complex compounds?
A. $CO$
B. $C{{H}_{4}}$
C. $C{{N}^{-}}$
D. $B{{r}^{-}}$
Answer
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Hint: Ligand is a molecule or ion that forms a bond with the central metal atom and forms a complex. The ligand should contain a lone pair of electrons or unpaired electrons in their orbitals to form a bond with the central metal atom to form coordination complexes.
Complete step by step answer:
- In the question it is given that which molecule/ion among the given options cannot act as a ligand in complex compounds.
- We have to find the molecule which does not act as a ligand in the given options.
- Coming to the given options, option A CO. We know that the oxygen atom has two lone pairs of electrons. Then carbon monoxide acts as a good ligand and forms a bond with the central metal atom.
- Coming to option B, methane. Methane does not contain any lone pair of electrons and unpaired electrons in its valence shell. So, methane does not act as a ligand.
- Coming to the option C, $C{{N}^{-}}$ . Cyanide ion has extra electrons in its valence shell then it will donate the electrons to the metal atom very easily. So, cyanide acts as a good ligand.
- Coming to the option D, $B{{r}^{-}}$ . Bromide ion has extra electrons in its valence shell then it will donate the electrons to the metal atom very easily. So, bromide acts as a good ligand.
- Therefore methane does not act as a ligand due to the absence of lone pair and valence electrons and it does not act as a ligand.
So, the correct option is B.
Note: In coordination complexes the metal is going to accept the electrons donated by the ligand and forms a complex. If the ligands donate electrons very easily then the ligand is called strong ligand and if the ligand donates electrons with some effort then the ligands are called weak ligands.
Complete step by step answer:
- In the question it is given that which molecule/ion among the given options cannot act as a ligand in complex compounds.
- We have to find the molecule which does not act as a ligand in the given options.
- Coming to the given options, option A CO. We know that the oxygen atom has two lone pairs of electrons. Then carbon monoxide acts as a good ligand and forms a bond with the central metal atom.
- Coming to option B, methane. Methane does not contain any lone pair of electrons and unpaired electrons in its valence shell. So, methane does not act as a ligand.
- Coming to the option C, $C{{N}^{-}}$ . Cyanide ion has extra electrons in its valence shell then it will donate the electrons to the metal atom very easily. So, cyanide acts as a good ligand.
- Coming to the option D, $B{{r}^{-}}$ . Bromide ion has extra electrons in its valence shell then it will donate the electrons to the metal atom very easily. So, bromide acts as a good ligand.
- Therefore methane does not act as a ligand due to the absence of lone pair and valence electrons and it does not act as a ligand.
So, the correct option is B.
Note: In coordination complexes the metal is going to accept the electrons donated by the ligand and forms a complex. If the ligands donate electrons very easily then the ligand is called strong ligand and if the ligand donates electrons with some effort then the ligands are called weak ligands.
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