
Which molecule is linear?
A.$N{O_2}$
B.$Cl{O_2}$
C.$C{O_2}$
D.${H_2}S$
Answer
456.3k+ views
Hint:If a compound that has no solitary sets of electrons, it will shape into a direct compound as the hydrogens will repulse each other however much as could reasonably be expected to make a straight line.
Complete answer:
The central atom of carbon dioxide is carbon, which is doubly attached to the two oxygen ions. It is tetravalent, which implies that it can shape bonds. The electrons encompassing the ion makes a 180 degrees angle in the particle, which makes it structure a linear molecular geometry.
Commonly, the assurance of sub-atomic geometry includes the 3-dimensional arrangement of substrates appended (attached) to a 'focal' component of a 'double bond' structure. The binary consideration for a linear sub-atomic geometry would be experimentally founded on an$A{X_2}$ atomic equation with 'A' being the focal component and X's the connected substrates. The $A{X_n}$ is most generally utilized however the accompanying strategy can be applied to $X - A - Y$ structures where there are various substrates joined to the focal component.
Thus, based on the above explanation we can say that the correct answer from the above given molecules in option is option C, $C{O_2}$.
Note:
For binary systems two things in the structure need to be resolved ...
(1) The number of bonded pair of electrons
(2) The number of non-bonded pair of electrons
The number of bonded pairs is equivalent to the quantity of substrates appended to the focal component of the binary compound and speaks to the quantity of 'Bonded Pairs' of electrons.
The number of non-bonded pair is somewhat more engaged with that one needs to utilize the articulation below:
Non-Bonded Pair = $\dfrac{\text{Valence Electrons - substrate electrons}}{2}$
Complete answer:
The central atom of carbon dioxide is carbon, which is doubly attached to the two oxygen ions. It is tetravalent, which implies that it can shape bonds. The electrons encompassing the ion makes a 180 degrees angle in the particle, which makes it structure a linear molecular geometry.
Commonly, the assurance of sub-atomic geometry includes the 3-dimensional arrangement of substrates appended (attached) to a 'focal' component of a 'double bond' structure. The binary consideration for a linear sub-atomic geometry would be experimentally founded on an$A{X_2}$ atomic equation with 'A' being the focal component and X's the connected substrates. The $A{X_n}$ is most generally utilized however the accompanying strategy can be applied to $X - A - Y$ structures where there are various substrates joined to the focal component.
Thus, based on the above explanation we can say that the correct answer from the above given molecules in option is option C, $C{O_2}$.
Note:
For binary systems two things in the structure need to be resolved ...
(1) The number of bonded pair of electrons
(2) The number of non-bonded pair of electrons
The number of bonded pairs is equivalent to the quantity of substrates appended to the focal component of the binary compound and speaks to the quantity of 'Bonded Pairs' of electrons.
The number of non-bonded pair is somewhat more engaged with that one needs to utilize the articulation below:
Non-Bonded Pair = $\dfrac{\text{Valence Electrons - substrate electrons}}{2}$
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