Which is not a correct relationship?
(A)- \[{{\left[ \dfrac{dH}{dT} \right]}_{P}}-{{\left[ \dfrac{dU}{dT} \right]}_{V}}=-ve\]
(B)- \[{{\left[ \dfrac{dU}{dV} \right]}_{T}}=0\] for an ideal gas
(C)- \[{{\left[ \dfrac{dV}{dT} \right]}_{_{P}}}=\dfrac{nR}{P}\] for an ideal gas
(D)- None
Answer
613.2k+ views
Hint: Cp is the heat capacity at constant pressure and is equal to the rate of change of enthalpy at constant pressure. Cv is the heat capacity at constant volume and is defined at the rate of change of energy at constant volume.
Complete step by step solution:
Let's look why some options are incorrect.
-Energy (U) is a function of temperature. It id dependent on the temperature of the gas. If change in temperature is 0 then change in energy will also be 0. So, for an ideal gas \[{{\left[ \dfrac{dU}{dV} \right]}_{T}}=0\]is true. Hence OPTION (B) is incorrect as we have to choose the incorrect statement.
-From the ideal gas equation, we get,
\[PV=nRT\]
Now, to get the desired result we will differentiate both sides
\[PdV+VdP=nRdT\]
Now, at constant pressure, dp=0
Therefore, \[P{{(dV)}_{P}}=nR{{(dT)}_{P}}\]
\[{{\left[ \dfrac{dV}{dT} \right]}_{_{P}}}=\dfrac{nR}{P}\] for an ideal gas
So, the above result is true for an ideal gas.
Hence, OPTION (C) is incorrect as we have to choose the false statement.
- Cp is the heat capacity at constant pressure and is equal to the rate of change of enthalpy at constant pressure. Cv is the heat capacity at constant volume and is defined at the rate of change of energy at constant volume.
Therefore, Cp \[={{\left[ \dfrac{dH}{dT} \right]}_{P}}\]and Cv \[={{\left[ \dfrac{dU}{dT} \right]}_{V}}\]
Now, we know that Cp is greater than Cv. So the difference of them should be positive but in the OPTION (A) it is given that,
\[{{\left[ \dfrac{dH}{dT} \right]}_{P}}-{{\left[ \dfrac{dU}{dT} \right]}_{V}}= -ve\] which is an incorrect statement.
Hence option (A) is the correct answer to the above question.
Note: Cp is greater than Cv as when heat is supplied at constant volume then no work is done, only temperature is increased but when heat is supplied at constant pressure then work is done also.
Complete step by step solution:
Let's look why some options are incorrect.
-Energy (U) is a function of temperature. It id dependent on the temperature of the gas. If change in temperature is 0 then change in energy will also be 0. So, for an ideal gas \[{{\left[ \dfrac{dU}{dV} \right]}_{T}}=0\]is true. Hence OPTION (B) is incorrect as we have to choose the incorrect statement.
-From the ideal gas equation, we get,
\[PV=nRT\]
Now, to get the desired result we will differentiate both sides
\[PdV+VdP=nRdT\]
Now, at constant pressure, dp=0
Therefore, \[P{{(dV)}_{P}}=nR{{(dT)}_{P}}\]
\[{{\left[ \dfrac{dV}{dT} \right]}_{_{P}}}=\dfrac{nR}{P}\] for an ideal gas
So, the above result is true for an ideal gas.
Hence, OPTION (C) is incorrect as we have to choose the false statement.
- Cp is the heat capacity at constant pressure and is equal to the rate of change of enthalpy at constant pressure. Cv is the heat capacity at constant volume and is defined at the rate of change of energy at constant volume.
Therefore, Cp \[={{\left[ \dfrac{dH}{dT} \right]}_{P}}\]and Cv \[={{\left[ \dfrac{dU}{dT} \right]}_{V}}\]
Now, we know that Cp is greater than Cv. So the difference of them should be positive but in the OPTION (A) it is given that,
\[{{\left[ \dfrac{dH}{dT} \right]}_{P}}-{{\left[ \dfrac{dU}{dT} \right]}_{V}}= -ve\] which is an incorrect statement.
Hence option (A) is the correct answer to the above question.
Note: Cp is greater than Cv as when heat is supplied at constant volume then no work is done, only temperature is increased but when heat is supplied at constant pressure then work is done also.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Which among the following are examples of coming together class 11 social science CBSE

Discuss the various forms of bacteria class 11 biology CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a labelled diagram showing structure of LS of class 11 biology CBSE

