Question

Which is greater: $ - \dfrac{2}{9}\,or\,0$ ?

Answer 1

Hint: In order to this question, to know which is the greater number $ - \dfrac{2}{9}\,or\,0$ , we will discuss how number line works or how we can understand the concept of number line, we will also discuss how negative signs integers is smaller than the positive signs integers.

Complete step by step answer:
$0$ is always greater than any of the negative integers like $ - \dfrac{2}{9}$ . As we know, on a number line- the left hand side numbers from the point where 0 is placed is always smaller than the numbers on the right hand side from the 0. And also negative integers are left from $0$, so they are also smaller than 0. Zero is neither negative nor positive.

Or in the simplest words, the integers with negative(-) signs are always smaller than zero and the positive integers that don't contain negative(-) signs. That means, the numbers containing negative signs with them always have their value less than zero(0). The concept of positive and negative is based on the number zero. Positive numbers are those that are greater than zero, whereas negative numbers are those that are less than zero.

The numbers are either positive or negative in our minds. However, all real numbers fall into one of three categories: positive, negative, or zero. This is one of the reasons why zero can get lost in the shuffle. With so many other numbers that can be positive or negative, zero is genuinely unique.

Hence, $0$ is greater than $ - \dfrac{2}{9}$.

Note:Zero is like a neutral ground, it is greater than negative values. It isn't a pro or a negative, and it isn't necessarily regarded higher or lower; it is simply a component to examine. Zero is absolutely a number. It has some special properties that other numbers do not have, but that doesn’t make it not a number.