
Which has melting point below ${{500}^{\circ }}C$?
(A)- $Ag$, $Cu$
(B)- $Zn$, $Cd$
(C)- $Cd$, $Cu$
(D)- $Ag$, $Zn$
Answer
578.4k+ views
Hint: The melting point of the transition metals is very high of the metallic bonds they form because of the vacant d-orbital present in their orbitals but the last element of each period has a very low melting point because of the completely filled orbital.
Complete step by step solution:
All the elements present in the above options belong to the transition element. $Zn$ is the zinc, $Cu$ is the copper, $Cd$ is the cadmium, and $Ag$ is the silver.
The melting point of the transition metals is very high in the metallic bonds they form because of the vacant d-orbital present in their orbitals. Due to the presence of vacant d-orbital and very high heat of atomization, they form a strong metallic bond, which requires high energy to break and they have a high melting point.
But the last element of each period has a very low melting point because of the completely filled orbital and due to this completely filled d-orbital, they are not available for making metallic bonds with other elements. So they have a low heat of atomization and low melting point.
So the melting point of zinc is ${{419}^{\circ }}C$, cadmium is ${{321.07}^{\circ }}C$, copper is ${{1084}^{\circ }}C$, and silver is ${{961}^{\circ }}C$. Since zinc is the last element of 3d series and cadmium is the last element of the 4d series.
Therefore, the correct answer is an option (B)- $Zn$, $Cd$.
Note: Enthalpy of heat atomization is the heat needed to break the lattice of the metal to get free atoms or ions. In the transition metals, tungsten ($W$) has the highest melting point and mercury ($Hg$) has the least.
Complete step by step solution:
All the elements present in the above options belong to the transition element. $Zn$ is the zinc, $Cu$ is the copper, $Cd$ is the cadmium, and $Ag$ is the silver.
The melting point of the transition metals is very high in the metallic bonds they form because of the vacant d-orbital present in their orbitals. Due to the presence of vacant d-orbital and very high heat of atomization, they form a strong metallic bond, which requires high energy to break and they have a high melting point.
But the last element of each period has a very low melting point because of the completely filled orbital and due to this completely filled d-orbital, they are not available for making metallic bonds with other elements. So they have a low heat of atomization and low melting point.
So the melting point of zinc is ${{419}^{\circ }}C$, cadmium is ${{321.07}^{\circ }}C$, copper is ${{1084}^{\circ }}C$, and silver is ${{961}^{\circ }}C$. Since zinc is the last element of 3d series and cadmium is the last element of the 4d series.
Therefore, the correct answer is an option (B)- $Zn$, $Cd$.
Note: Enthalpy of heat atomization is the heat needed to break the lattice of the metal to get free atoms or ions. In the transition metals, tungsten ($W$) has the highest melting point and mercury ($Hg$) has the least.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

The draft of the Preamble of the Indian Constitution class 10 social science CBSE

Who gave "Inqilab Zindabad" slogan?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

