
Which element has the lowest melting and boiling point.
A. $Ti$
B. $Cu$
C. $Zn$
D. $Mn$
Answer
571.5k+ views
Hint: Here all the mentioned elements are from the same group of the periodic table, hence they are easily comparable. We just have to see all the approaches we need to observe the change of boiling and melting point of the elements. By the observation we get that we have to apply the concept of electron exchange in interatomic bonding. Then we get the answer by observing the $d$ subshell.
Complete step by step answer:
Here to compare and observe the pattern for the boiling point we have to look forward to various physical characteristics of the given elements. They are as follows :
-Number of the electrons involved from $(n - 1)d$ in the addition to the electrons to the $ns$ subshell. -This is the process of the interatomic bonding.
The type of the element
-The physical state of the element
-Whether the element is metal, non-metal or metalloid.
-In the upward given question we have to use the first approach to observe the change or the difference between the given atoms or elements.
-Here when we observe the number of electrons involved from $(n - 1)d$ in the addition to the electrons to the $ns$ subshell, we observe that:
-$Zn$ is the element with no unpaired electron hence it will have the lowest melting and boiling point.
Therefore the answer would be option B, False.
Note: Here we have all the elements from the same group so we can apply a specific approach. When the elements are diversified ( from different groups ) then we have to use the basic way of comparison along with the approach. That is that the melting and boiling point decreases down the table.
Complete step by step answer:
Here to compare and observe the pattern for the boiling point we have to look forward to various physical characteristics of the given elements. They are as follows :
-Number of the electrons involved from $(n - 1)d$ in the addition to the electrons to the $ns$ subshell. -This is the process of the interatomic bonding.
The type of the element
-The physical state of the element
-Whether the element is metal, non-metal or metalloid.
-In the upward given question we have to use the first approach to observe the change or the difference between the given atoms or elements.
-Here when we observe the number of electrons involved from $(n - 1)d$ in the addition to the electrons to the $ns$ subshell, we observe that:
-$Zn$ is the element with no unpaired electron hence it will have the lowest melting and boiling point.
Therefore the answer would be option B, False.
Note: Here we have all the elements from the same group so we can apply a specific approach. When the elements are diversified ( from different groups ) then we have to use the basic way of comparison along with the approach. That is that the melting and boiling point decreases down the table.
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