Question

Which element exhibits the highest density in $3d$ series?
 A.$Sc$
 B.$Cr$
 C.$Zn$
 D.$Cu$

Answer 1

Hint: We have to know that thickness estimation is utilized to indicate and depict an unadulterated substance, yet additionally decides centralizations of paired blends and in this manner gives data about the creation of combinations. It is, for instance, valuable during quality control or decides the filling volume during the packaging of an item.

Complete answer:
We have to know that, the d-block components are the components which can be found from the third gathering to the twelfth gathering of the cutting edge intermittent table. The valence electrons of these components fall under the d orbital. d-block components are likewise alluded to as change components or progress metals. The initial three lines of the d square components which compare to the $3d$ , $4d$ , and $5d$ orbitals.
Components having electrons ($1$ to $10$) present in the d-orbital of the penultimate energy level and in the external most 's' orbital ($1 - 2$) are d square components. Despite the fact that electrons don't top off 'd' orbital in the gathering twelve metals, their science is comparative from multiple points of view to that of the first gatherings, thus considered as d-block components.
The $3d$ series elements are given below,
Scandium, titanium, vanadium, chromium, manganese, iron, cobalt, nickel copper, zinc.
In the $3d$ arrangement, scandium has the least thickness and copper the most elevated thickness.

Therefore, the correct option is (D).

Note:
We have to see that the transition metals are utilized as impetuses from numerous points of view. We utilize metal surfaces with oxides to make alkali. This is the most conservative approach to create smelling salts, and is exceptionally utilized in composts. The metal surface can adsorb components and mixtures into itself.