
Which contains at least one $ {e^ - } $ in $ \sigma 2p $ bonding MO:
(A) $ {O_2} $
(B) $ {B_2} $
(C) $ {C_2} $
() $ L{i_2} $
Answer
498.6k+ views
Hint :This question is based on the widely used concept of representation of electronic configuration with the help of molecular orbitals. This is an advanced representation of electronic configuration and it has cleared a lot of dilemmas regarding the presence of various exceptional cases in the context of relation between electronic configuration and the properties of the element.
Complete Step By Step Answer:
The valence-bond theory failed to adequately explain how certain compounds, such as resonance-stabilized compounds, contain two or more analogous bonds whose bond orders lie between those of a single bond and those of a double bond. The molecular orbital theory was shown to be more powerful than the valence-bond hypothesis in this case (since the orbitals described by the MOT reflect the geometries of the molecules to which it is applied).
The molecular orbital theory states, in simple terms, that each atom tends to join and form molecular orbitals. Electrons are found in distinct atomic orbitals as a result of this arrangement, and they are frequently connected with different nuclei. In a molecule, an electron can be found anywhere in the molecule.
In the above question, $ {O_2} $ has 16 electrons, which can be arranged in a certain manner in atomic orbitals:
$ {O_2} = {(\sigma 1s)^2}{({\sigma ^*}1s)^2}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{(\sigma 2{p_z})^2}(\pi 2{p_x}^2 = \pi 2{p_y}^2)({\pi ^*}2{p_x}^1 = {\pi ^*}2{p_y}^1) $
So, it can clearly be observed that it has more than one electron in $ \sigma 2p $ orbital.
So, the correct answer is (A).
Note :
One of the most significant effects of the molecular orbital theory after its formulation was that it opened up new avenues for understanding the bonding process. According to this idea, molecule orbitals are essentially linear combinations of atomic orbitals. The Schrödinger equation is further approximated using the Hartree–Fock (HF) or density functional theory (DFT) models.
Complete Step By Step Answer:
The valence-bond theory failed to adequately explain how certain compounds, such as resonance-stabilized compounds, contain two or more analogous bonds whose bond orders lie between those of a single bond and those of a double bond. The molecular orbital theory was shown to be more powerful than the valence-bond hypothesis in this case (since the orbitals described by the MOT reflect the geometries of the molecules to which it is applied).
The molecular orbital theory states, in simple terms, that each atom tends to join and form molecular orbitals. Electrons are found in distinct atomic orbitals as a result of this arrangement, and they are frequently connected with different nuclei. In a molecule, an electron can be found anywhere in the molecule.
In the above question, $ {O_2} $ has 16 electrons, which can be arranged in a certain manner in atomic orbitals:
$ {O_2} = {(\sigma 1s)^2}{({\sigma ^*}1s)^2}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{(\sigma 2{p_z})^2}(\pi 2{p_x}^2 = \pi 2{p_y}^2)({\pi ^*}2{p_x}^1 = {\pi ^*}2{p_y}^1) $
So, it can clearly be observed that it has more than one electron in $ \sigma 2p $ orbital.
So, the correct answer is (A).
Note :
One of the most significant effects of the molecular orbital theory after its formulation was that it opened up new avenues for understanding the bonding process. According to this idea, molecule orbitals are essentially linear combinations of atomic orbitals. The Schrödinger equation is further approximated using the Hartree–Fock (HF) or density functional theory (DFT) models.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

